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MAGNETIC FIELDS DUE TO CURRENTS

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PHY110W MAGNETISM <strong>MAGNETIC</strong> <strong>FIELDS</strong> <strong>DUE</strong> <strong>TO</strong> <strong>CURRENTS</strong><br />

<strong>MAGNETIC</strong> FIELD <strong>DUE</strong> <strong>TO</strong> CURRENT<br />

IN A LONG, STRAIGHT WIRE<br />

d s <br />

i<br />

s<br />

θ<br />

R<br />

r<br />

× dB<br />

P<br />

Using symmetry (every current element ds in the upper<br />

half of the wire has a corresponding element in the<br />

lower half causing the same field at P), the magnitude<br />

of the magnetic field at point P due to a long, straight,<br />

current-carrying wire is<br />

∞<br />

0i<br />

2 4<br />

µ<br />

B = sinθ<br />

ds<br />

π ∫ (30-7)<br />

2<br />

r<br />

0<br />

= ° − =<br />

R<br />

, and<br />

r<br />

where sinθ<br />

sin( 180 θ)<br />

∴ B =<br />

µ 0i<br />

2π<br />

∞<br />

∫<br />

0<br />

R<br />

(<br />

2 2)<br />

s<br />

+<br />

R<br />

32<br />

ds<br />

2 2<br />

r = s + R<br />

∞<br />

µ 0i<br />

⎡ s ⎤<br />

∴ B = 12<br />

2π<br />

R ⎢( 2 2<br />

s R ) ⎥<br />

⎣ + ⎦0<br />

µ 0i<br />

∴ B = (30-6)<br />

2π<br />

R<br />

The direction of B is given by the RH curled fingers rule.<br />

14

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