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Chapter 9: Introduction to Hypothesis Testing

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408 CHAPTER 9 • INTRODUCTION TO HYPOTHESIS TESTING<br />

The null hypothesis is false for all possible values of 700 hours. Thus, for each of the<br />

infinite number of possibilities, a value of can be determined. (Note: is assumed <strong>to</strong> be a<br />

known value of 15 hours.)<br />

Figure 9.9 shows how is calculated if the true value of is 701 hours. By specifying<br />

the significance level <strong>to</strong> be 0.05 and a sample size of 100 bulbs, the chance of committing<br />

a Type II error is approximately 0.8365. This means that if the true population mean is 701<br />

hours, there is nearly an 84% chance that the sampling plan American Lighting is using<br />

will not reject the assumption that the mean is 700 hours or less.<br />

Figure 9.10 shows that if the “what-if” mean value ( 704) is farther from the<br />

hypothesized mean ( 700), beta becomes smaller. The greater the difference between<br />

the mean specified in H 0<br />

and the mean selected from H A<br />

, the easier it is <strong>to</strong> tell the two apart,<br />

and the less likely we are <strong>to</strong> not reject the null hypothesis when it is actually false. Of course<br />

the opposite is also true. As the mean selected from H A<br />

moves increasingly closer <strong>to</strong> the<br />

mean specified in H 0<br />

, the harder it is for the hypothesis test <strong>to</strong> distinguish between the two.<br />

Controlling Alpha and Beta<br />

Ideally, we want both alpha and beta <strong>to</strong> be as small as possible. Although we can set alpha<br />

at any desired level, for a specified sample size and standard deviation, the calculated value<br />

of beta depends on the population mean chosen from the alternative hypothesis and the significance<br />

level. For a specified sample size, reducing alpha will increase beta. However, we<br />

FIGURE 9.9<br />

Beta Calculation for<br />

True µ 701<br />

Hypothesized<br />

Distribution<br />

Rejection region<br />

α = 0.05<br />

x 0.05 = μ + z 0.05<br />

σ<br />

n<br />

x 0.05 = 700 + 1.645<br />

x 0.05 = 702.468<br />

15<br />

100<br />

0<br />

μ = 700<br />

z<br />

z 0.05 = 1.645<br />

x 0.05 = 702.468<br />

Beta<br />

“True” Distribution<br />

0<br />

μ = 701<br />

z = 0.98<br />

x 0.05 = 702.468<br />

z<br />

z =<br />

x 0.05 – μ = 702.468 − 701 = 0.98<br />

σ/ n<br />

15<br />

100<br />

From the standard normal table, P(0 z 0.98) = 0.3365<br />

Beta = 0.5000 + 0.3365 = 0.8365

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