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My PhD thesis - Condensed Matter Theory - Imperial College London

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CHAPTER 8. APPLYING THE PLASMON NORMAL MODE THEORY TO<br />

SLAB SYSTEMS<br />

8.2.1 Approximate analytic solution for an infinite slab<br />

It is possible to obtain an approximation to u pl by taking the slab width s and the<br />

cell size L to infinity, in which case the sums become integrals:<br />

∑<br />

→ s π<br />

k z>0<br />

∫ ∞<br />

0<br />

dk z (8.94)<br />

∑<br />

∫ ∞ ∫ ∞<br />

→ L2<br />

dk<br />

(2π) 2 x dk y (8.95)<br />

k<br />

−∞ 0<br />

‖<br />

The system is no longer a slab but a single surface (at z = 0) of infinite extent in<br />

the x- and y-directions.<br />

Note that a further approximation has also been introduced here: the k-space<br />

cut-off described in the previous section has been neglected in order to enable the<br />

integrals to be solved analytically.<br />

In this limit, the bulk term becomes<br />

∫<br />

u ∞ bulk(r, r ′ ) =<br />

e2 4<br />

ω p ɛ 0 V k k cos k 2 ‖ · (r ‖ − r ′ ‖) sin k z z sin k z z ′ V d 3 k<br />

π(2π) 2 Θ(z)Θ(z′ )<br />

e 2 ∫ ∞<br />

)<br />

=<br />

dk<br />

2π 3 z<br />

(cos k z (z − z ′ ) − cos k z (z + z ′ )<br />

ɛ 0 ω p<br />

×<br />

∫ ∞<br />

0<br />

dk ‖<br />

0<br />

k ‖<br />

k 2 ‖ + k2 z<br />

∫ π<br />

0<br />

dθ cos ( k ‖ ∆r ‖ cos(θ − φ) ) Θ(z)Θ(z ′ ) (8.96)<br />

where ∆r ‖ = r ‖ − r ′ ‖ and φ = tan−1 (∆y/∆x). Performing the integration gives<br />

u ∞ bulk(r, r ′ ) =<br />

=<br />

e 2 ∫ ∞<br />

2π 3 ɛ 0 ω p 0<br />

∫ ∞<br />

k ‖<br />

×<br />

0<br />

e 2 ∫ ∞<br />

2π 2 ɛ 0 ω p<br />

0<br />

)<br />

dk z<br />

(cos k z (z − z ′ ) − cos k z (z + z ′ ) Θ(z)Θ(z ′ )<br />

( )<br />

dk ‖<br />

k‖ 2 + πJ 0 k‖ ∆r ‖ Θ(z)Θ(z ′ )<br />

k2 z<br />

( )<br />

dk z<br />

(cos k z (z − z ′ ) − cos k z (z + z ′ )<br />

)K 0 kz ∆r ‖<br />

× Θ(z)Θ(z ′ )<br />

(<br />

)<br />

e 2<br />

π<br />

=<br />

2π 2 ɛ 0 ω p 2 √ (z − z ′ ) 2 + (∆r ‖ ) − π<br />

2 2 √ Θ(z)Θ(z ′ )<br />

(z + z ′ ) 2 + (∆r ‖ ) 2<br />

( √ )<br />

e 2<br />

1<br />

=<br />

1 −<br />

Θ(z)Θ(z ′ ). (8.97)<br />

4πɛ 0 ω p |r − r ′ | 1 + 4zz′<br />

|r−r ′ | 2<br />

141

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