Exam style questions - Hodder Plus Home
Exam style questions - Hodder Plus Home
Exam style questions - Hodder Plus Home
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<strong>Exam</strong> <strong>questions</strong>: Unit A<br />
4 Bob and Eddie each collect pebbles from two different places on a beach. They measure the maximum<br />
diameter of 20 pebbles they have collected and record the data. All the measurements are in centimetres.<br />
Bob records his measurements in a stem-and-leaf diagram:<br />
1 0<br />
2 0 1 2 2 5 5 7 8<br />
3 0 0 1 1 3 4 7 8 9<br />
4 0 6<br />
Key 1 ⏐ 9 means 1.9 cm<br />
a Write down the range and the median diameter of Bob’s pebbles. [2]<br />
Eddie’s pebbles have the following measurements.<br />
1.2 5.5 2.2 2.1 3.4<br />
1.8 4.5 3.2 3.0 1.4<br />
3.3 4.9 2.1 2.1 2.8<br />
4.8 4.2 1.9 3.8 1.1<br />
b Draw a stem-and-leaf diagram for Eddie’s pebbles and find the range and median. [2 + 2 + 1]<br />
c Compare the two distributions. [2]<br />
5 The numbers below show how many correct answers each person had in a quiz.<br />
23 12 21 24 18 15 20 19 22 21 17 16<br />
9 20 23 21 18 27 25 28 29 23 14 23<br />
21 25 19 23 20 30 24 2 26 13 27 18<br />
a Draw an ordered stem-and-leaf diagram to show this information. [3]<br />
b What was the range of the scores [1]<br />
c What was the modal score [1]<br />
17 Equations 2<br />
Here is an exam question …<br />
Solve the following equations.<br />
a 2(3 − x) = 1 [3]<br />
b 5 x + 8 = 6<br />
[3]<br />
3<br />
c 4(x + 7) = 3(2x − 4) [4]<br />
… and its solution<br />
a 2(3 − x) = 1<br />
6 − 2x = 1<br />
−2x = −5<br />
x = 2 1 2<br />
b 5 x + 8 = 6<br />
3<br />
5x + 8 = 18<br />
5x = 10<br />
x = 2<br />
c 4(x + 7) = 3(2x − 4)<br />
4x + 28 = 6x − 12<br />
40 = 2x<br />
x = 20<br />
Now try these exam <strong>questions</strong><br />
1 Solve these.<br />
a 3x = x + 1 [2]<br />
b 3p − 4 = p + 8 [3]<br />
c 3 m = 9<br />
4<br />
[2]<br />
2 Solve 3(p − 4) = 36. [3]<br />
3 Solve 4(x − 1) = 2x + 3. [3]<br />
16 Revision Notes © <strong>Hodder</strong> Education 2011