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Exam style questions - Hodder Plus Home

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4 ‘Doggy Planet’ sell pet goods by post.<br />

They record the weight of each<br />

package sent by post one day.<br />

Calculate an estimate of the mean<br />

weight of a package.<br />

Weight of package (w kg)<br />

Frequency<br />

0 w < 5 6<br />

5 w < 10 11<br />

10 w < 15 23<br />

15 w < 20 8<br />

20 w < 25 2<br />

[4]<br />

5 The table shows the number of text messages received by each of 80 people in a single week.<br />

Number of messages received<br />

Frequency<br />

1 to 20 12<br />

21 to 40 31<br />

41 to 60 22<br />

61 to 80 11<br />

81 to 100 4<br />

Calculate an estimate of the mean number of messages received per person during the week. [4]<br />

20 Pythagoras’<br />

theorem<br />

b a 2 = b 2 + c 2<br />

= 4.6 2 + 5.0 2<br />

= 46.16<br />

a = 46.<br />

16<br />

a = 6.8 cm (to 1 d.p.)<br />

Here is an exam question ...<br />

Now try these exam <strong>questions</strong><br />

a Find the area of this triangle.<br />

1 The diagram shows the cross section of the end of<br />

a shed.<br />

The shed is 180 cm wide at ED and AC. The<br />

length of the roof AB is 110 cm. The height of the<br />

5.0 cm<br />

side AE is 2 m.<br />

What is the maximum height of the shed [5]<br />

4.6 cm<br />

B<br />

b Calculate the length of the hypotenuse of this<br />

triangle. Give your answer to a sensible degree<br />

A<br />

C<br />

of accuracy. [5]<br />

... and its solution<br />

a Area of triangle = 1 2<br />

base × height<br />

= 1 2<br />

× 4.6 × 5.0<br />

= 11.5 cm<br />

E<br />

D<br />

© <strong>Hodder</strong> Education 2011 Unit A<br />

19

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