CHAPTER Surface Area - School District #35
CHAPTER Surface Area - School District #35
CHAPTER Surface Area - School District #35
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5.3 <strong>Surface</strong> <strong>Area</strong> of a Prism<br />
surface area<br />
• the number of square units needed to cover all the faces of<br />
a 3-D object<br />
• the sum of the areas of all the faces of an object<br />
• measured in square units (cm 2 , m 2 )<br />
Working Example 1: Calculate the <strong>Surface</strong> <strong>Area</strong> of a Right Rectangular Prism<br />
a) Draw the net of this right rectangular prism.<br />
Solution<br />
4 cm<br />
10 cm<br />
10 cm<br />
6 cm<br />
front or back<br />
top or bottom<br />
6 cm<br />
4 cm<br />
10 cm<br />
10 cm<br />
= 10 ×<br />
= cm 2<br />
<strong>Area</strong> of top and bottom<br />
= 40 × 2<br />
= cm 2<br />
b) What is the surface area of the prism<br />
Solution<br />
The right rectangular prism has 6 faces. There are 3 different sizes of faces.<br />
A = l × w<br />
= 10 × 6<br />
=<br />
<strong>Area</strong> of front<br />
= 60 × 2<br />
=<br />
cm 2<br />
back<br />
cm 2 A = l × w<br />
= cm 2 A = l × w<br />
= 6 ×<br />
=<br />
<strong>Area</strong> of<br />
= 24 × 2<br />
=<br />
cm 2<br />
sides<br />
cm 2<br />
and both<br />
<strong>Surface</strong> <strong>Area</strong> = (area of front and back) + (area of top and bottom) + (area of ends)<br />
= 120 + 80 + 48<br />
6 cm<br />
4 cm<br />
4 cm<br />
ends<br />
6 cm<br />
246 MHR ● Chapter 5: <strong>Surface</strong> <strong>Area</strong>
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