CHAPTER Surface Area - School District #35
CHAPTER Surface Area - School District #35
CHAPTER Surface Area - School District #35
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Working Example 2: Calculate the <strong>Surface</strong> <strong>Area</strong> of a Right Triangular Prism<br />
a) Draw the net of this right triangular prism.<br />
Solution<br />
9 m<br />
9 m<br />
3 m<br />
2.6 m<br />
3 m<br />
2.6 m<br />
b) What is the surface area<br />
3 sides with the same length<br />
Solution<br />
The bases of the prism are equilateral triangles. The sides of the prism are rectangles.<br />
rectangle<br />
triangle<br />
3 m<br />
2.6 m<br />
9 m<br />
A = l × w<br />
A = (b × h) ÷ 2<br />
= m 2<br />
= 9 ×<br />
= (3 × 2.6) ÷ 2<br />
3 m<br />
= ÷ 2<br />
= m 2<br />
The right triangular prism has 5 faces.<br />
A =<br />
A =<br />
A =<br />
A =<br />
A =<br />
<strong>Surface</strong> <strong>Area</strong> = (3 × area of rectangle) + (2 × area of triangle)<br />
= (3 × 27) + (2 × 3.9)<br />
= +<br />
248 MHR ● Chapter 5: <strong>Surface</strong> <strong>Area</strong><br />
=<br />
The surface area of the right triangular prism is m 2 .