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IEEE TRANS. SIGNAL PROC. 11<br />

Fig. 9.<br />

Left: Original (hexagonal) image; Right: Decomposed image with lowpass filter p<br />

Fig. 10.<br />

Decomposed images with highpass filters q (1) (left) <strong>and</strong> q (2) (right)<br />

A. 6-fold axial symmetry<br />

Let<br />

<strong>and</strong> denote<br />

[ ] [ ] [ 0 1<br />

1 0<br />

1 −1<br />

L 0 = , L<br />

1 0 1 =<br />

, L<br />

1 −1 2 =<br />

0 −1<br />

L 3 = −L 0 , L 4 = −L 1 , L 5 = −L 2 ,<br />

R 1 =<br />

[ 0 1<br />

−1 1<br />

Then for a j, 0 ≤ j ≤ 5, {p k } is symmetric around the symmetry axis S j in Fig. 7 if <strong>and</strong> only if p Lj k = p k ; <strong>and</strong><br />

{p R1 k} is the π 3 (anticlockwise) rotation <strong>of</strong> {p k}.<br />

Observe that<br />

L j = (R 1 ) j L 0 , 0 ≤ j ≤ 5.<br />

Thus, instead <strong>of</strong> considering all L j , 0 ≤ j ≤ 5, we need only consider L 0 , R 1 when we discuss the 6-fold axial<br />

symmetry <strong>of</strong> a filter bank. First we have the following proposition.<br />

Proposition 1: A filter bank {p, q (1) , q (2) } has 6-fold axial symmetry if <strong>and</strong> only if it satisfies<br />

]<br />

.<br />

]<br />

,<br />

(25)<br />

[p, q (1) , q (2) ] T (R1 −T ω) = N 1 (ω)[p, q (1) , q (2) ] T (ω), (26)<br />

[p, q (1) , q (2) ] T (L 0 ω) = N 2 (ω)[p, q (1) , q (2) ] T (ω), (27)<br />

w<strong>here</strong><br />

⎡<br />

N 1 (ω) = ⎣<br />

1 0 0<br />

0 0 e −i(2ω 1+ω 2 )<br />

0 e i(2ω 1+ω 2 )<br />

0<br />

⎤<br />

⎡<br />

⎦ , N 2 (ω) = ⎣<br />

1 0 0<br />

0 e i(ω 1−ω 2 )<br />

0 0 e −i(ω 1−ω 2 )<br />

⎤<br />

⎦ . (28)<br />

Pro<strong>of</strong>. For a filter bank {p, q (1) , q (2) }, let h (1) (ω) = e iω 1 q(1) (ω), h (2) (ω) = e −iω 1 q(2) (ω). Then with the fact<br />

L j = R j 1 L 0, 0 ≤ j ≤ 5, we know {p, q (1) , q (2) } has 6-fold axial symmetry if <strong>and</strong> only if<br />

p(R1 −T ω) = p(L 0 ω) = p(ω), (29)<br />

h (1) ((R1 −T ) 2 ω) = h (1) ((R1 −T ) 4 ω) = h (1) (L 0 ω) = h (1) (ω), (30)<br />

h (2) (−ω) = h (1) (ω). (31)

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