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EQUATIONS OF ELASTIC HYPERSURFACES

EQUATIONS OF ELASTIC HYPERSURFACES

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5. BOUNDARY VALUE PROBLEMS: EXAMPLES 163<br />

Lemma 5.20 Let R(S ) be the finite dimensional linear space of Killing’s vector fields and<br />

X 1 R (S ) be the complemented space to R(S ) in X1 (S ) (cf. (3.159)). The Lamé operator<br />

(cf. (3.104) and (3.113)) maps the tangential spaces<br />

L S<br />

: X 1 2(S ) ⋂ V (S ) → X −1<br />

2 (S ) ⋂ V (S ) (5.88)<br />

is self adjoint L ∗ S = L S and elliptic. Its kernel coincides with the space of Killing’s vector<br />

fields<br />

Ker L S = {U ∈ V (S ) : L S U = 0} = R(S ) (5.89)<br />

and is positive definite on the complemented space X 1 R (S ):<br />

(L S U, U) S ≥ c ∥ ∥ U<br />

∣ ∣X 1 (S ) ∥ ∥ 2 for ∀U ∈ X 1 R(S ) , c > 0 . (5.90)<br />

Proof: Let us check the ellipticity of L S . The operator L S maps the tangential spaces and<br />

the image should be orthogonal to the normal vector ν. The principal symbol is defined on<br />

the cotangent space and is orthogoal to the normal vector as well. Therefore,<br />

L S (t, ξ)η = µ|ξ| 2 (1 − νν ⊤ )η + (λ + µ)ξξ ⊤ η = µ|ξ| 2 η + (λ + µ)ξξ ⊤ η ,<br />

∀ η ⊥ ν<br />

and while considering the principal symbol L S (t, ξ) we can ignore the projection π S . With<br />

this assumption, the principal symbol of L S reads<br />

L S (t, ξ) = µ|ξ| 2 + (λ + µ)ξξ ⊤ for (t, ξ) ∈ T ∗ (S ) . (5.91)<br />

The matrix L S (t, ξ) has eigenvalue (λ + 2µ)|ξ| 2 (the corresponding eigenvector is ξ) and<br />

µ|ξ| 2 which has multiplicity n − 1 (the corresponding eigenvectors θ j are orthogonal to ξ:<br />

ξ ⊤ θ j = 〈ξ, θ j 〉 = 0, j = 1, . . . , n − 1). Then<br />

det L S (t, ξ) = (λ + 2µ)|ξ| 2[ µ|ξ| 2] n−1<br />

= µ n−1 (λ + 2µ) > 0<br />

for (t, ξ) ∈ T ∗ (S ) , |ξ| = 1<br />

and the ellipticity is proved.<br />

To prove the remainder (5.89) and (5.90) we apply the representation (3.104):<br />

L S U = λ Div ∗ S Div S U + 2µ Def ∗ S Def S U = 0 provided Def S U = 0 . (5.92)<br />

In fact, Def S U = 0 implies D jj U = U j;j = D S j U j = 0 and, due to (3.70),<br />

0 =<br />

n∑<br />

Dj S U j =<br />

j=1<br />

n∑<br />

D j U j = Div S U .<br />

j=1<br />

Thence, due to (5.92), R(S ) ⊂ Ker L S . The inverse inclusion follows from the inequality<br />

(5.90) which we prove last:<br />

(L S U, U) S = λ(Div ∗ S Div S U, U) S + 2µ(Def ∗ S Def S U, U) S<br />

= λ ∥ ∥ DivS U ∣ ∣ L2 (S ) ∥ ∥ 2 + 2µ ∥ ∥ DefS U ∣ ∣ L2 (S ) ∥ ∥ 2<br />

≥2µ ∥ ∥ DefS U ∣ ∣ L2 (S ) ∥ ∥ 2 ≥ 2cµ ∥ ∥ U<br />

∣ ∣W 1 (S ) ∥ ∥ 2 for ∀U ∈ W 1 R(S ) ,<br />

for some c > 0 and due to the Korn’s inequality (3.160) in Corollary 3.38.

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