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EQUATIONS OF ELASTIC HYPERSURFACES

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3. CALCULUS <strong>OF</strong> DIFFERENTIAL OPERATORS ON <strong>HYPERSURFACES</strong> 69<br />

and therefore we get<br />

⎛<br />

⎜<br />

⎝<br />

=<br />

⎞<br />

∂ 1 N 1 · · · ∂ 1 N n<br />

.<br />

. ..<br />

⎟ . ⎠ =<br />

∂ n N 1 · · · ∂ n N n<br />

1 ( )<br />

∂j ∂ k Ψ S − N j ∂ N ∂ k Ψ S<br />

|∇Ψ S |<br />

1<br />

|∇Ψ S |<br />

Then (3.16) and (3.17) yields (3.15).<br />

Let θ(x) ∈ T x S then<br />

⎛<br />

⎜<br />

⎝<br />

⎞<br />

∂1Ψ 2 S · · · ∂ 1 ∂ n Ψ S<br />

.<br />

. ..<br />

⎟ . ⎠ (I n −N N ⊤ ). (3.17)<br />

∂ n ∂ 1 Ψ S · · · ∂nΨ 2 S<br />

W S (x)θ(x) = { N (x)N ⊤ (x) − I n<br />

}<br />

WS (x)θ(x).<br />

Thus the eigenvalues of the matrices W S (x) and<br />

A S (x) := { N (x)N ⊤ (x) − I n<br />

}<br />

WS (x) (3.18)<br />

coincide and denote them by {κ j (X )} 1≤j≤n , setting the last one zero: κ n = 0.<br />

From this representation we immediately have that the eigenvalues {κ j (x)} 1≤j≤n are the<br />

solutions of the following equation<br />

and the mean curvature is<br />

det(A S (x) − κ I) = 0<br />

H S (x) =<br />

∑n−1<br />

j=1<br />

κ j (x)<br />

n − 1 =<br />

n∑<br />

j=1<br />

TrA S (x)<br />

n − 1<br />

for x ∈ S .<br />

Let us now write (−1) n det(A S (x) − κ I) as a polynomial with respect to κ. Then the<br />

Gauß’s principal curvature at x ∈ S equals to the coefficient at κ.<br />

Example 3.9 Let us demonstrate obtained results for the ellipsoid Er,0 n−1 defined in (2.69).<br />

We have<br />

[ ]<br />

W E<br />

n−1 (x) = δ jk<br />

= diag ( α 1 (x), . . . , α n (x) ) ,<br />

r,0<br />

where<br />

α j (x) =<br />

R r,0 (x)rk<br />

2 n×n<br />

1<br />

rj 2R r,0(x) , N j(x) = x j α j (x) =<br />

R r,0 (x) :=<br />

[ n∑<br />

j=1<br />

(<br />

xj<br />

r 2 j<br />

) 2<br />

] 1/2<br />

.<br />

x j<br />

r 2 j R r,0(x) ,

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