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A report on an experiment I did of doing electrophoresis with proteins

A report on an experiment I did of doing electrophoresis with proteins

A report on an experiment I did of doing electrophoresis with proteins

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4<br />

FIG. 2: The above photograph shows green frames in which the gel is set <strong>an</strong>d the tr<strong>an</strong>sparent rack in which the green frames<br />

are clamped to keep them stable during the polymerizati<strong>on</strong> process.<br />

• Now <strong>on</strong>e mixes the APS <strong>an</strong>d the TEMED in the stacking soluti<strong>on</strong> <strong>an</strong>d pours it into the gap between the pairs<br />

<strong>of</strong> plates through a pipette in a similar fashi<strong>on</strong>. Now <strong>on</strong>e has to quickly insert the comb into the gap which will<br />

demarcate the wells that will form inside the stacking gel. This comb is not to be taken out untill the protein<br />

loading starts.<br />

• This set up should be left undisturbed till it is necessary to install the gels into the <strong>electrophoresis</strong> t<strong>an</strong>k.<br />

• Generally during this time <strong>on</strong>e starts making the chemicals that will be loaded into the gel. Like the diluti<strong>on</strong><br />

series <strong>of</strong> Actin <strong>an</strong>d BSA to be described below.<br />

C. Making Actin diluti<strong>on</strong> soluti<strong>on</strong><br />

When Actin is extracted it is not known as to how much Actin is present in the soluti<strong>on</strong>. It is estimated from<br />

indirect methods that the c<strong>on</strong>centrati<strong>on</strong> is 2µg/mul.<br />

The various steps in preparing the Actin diluti<strong>on</strong> are as follows,<br />

• I took 5 aliquots <strong>of</strong> the Actin soluti<strong>on</strong> which gave me about 43µl <strong>of</strong> Actin soluti<strong>on</strong>.<br />

• I added 117µl <strong>of</strong> H 2 O to it <strong>an</strong>d hence made up the soluti<strong>on</strong> to 160µl. Call this soluti<strong>on</strong> A 0<br />

• I took 80µl <strong>of</strong> A 0 <strong>an</strong>d added 80µl <strong>of</strong> H 2 O to it <strong>an</strong>d made 160µl <strong>of</strong> <strong>an</strong>other soluti<strong>on</strong>. Lets name it A 1<br />

• Again I took 80µl <strong>of</strong> A 1 <strong>an</strong>d added 80µl <strong>of</strong> H 2 O to it <strong>an</strong>d made 160 <strong>of</strong> <strong>an</strong>other soluti<strong>on</strong>. Lets name it A 2 .<br />

• Thus iterating the process about 5 times <strong>on</strong>e makes soluti<strong>on</strong>s <strong>of</strong> 80µl each till A 5 . In the making <strong>of</strong> A 5 the 80µl<br />

<strong>of</strong> A 4 that remains is preserved separately for future <strong>experiment</strong>s <strong>an</strong>d not used in the dyeing <strong>an</strong>d heating in the<br />

next steps.<br />

• In each <strong>of</strong> the 80µl soluti<strong>on</strong>s from A 0 to A 5 <strong>of</strong> Actin, 20µl <strong>of</strong> the “5X” DTT dye is added (so that in the final<br />

soluti<strong>on</strong> the dye is in c<strong>on</strong>centrati<strong>on</strong> <strong>of</strong> “1X”) <strong>an</strong>d then each <strong>of</strong> these 100µl soluti<strong>on</strong>s is sent for heating for 5mins<br />

at 100 ◦ C .<br />

• Post heating <strong>on</strong>e loads 20µl <strong>of</strong> each soluti<strong>on</strong> in each <strong>of</strong> the wells <strong>of</strong> the gel. Hence the amounts <strong>of</strong> protein in the<br />

wells <strong>of</strong> the gel fall in inverse powers <strong>of</strong> two.

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