(A V,.”)00 = ~ s*a = (D,. + ~ A,.ym) —314 P. <strong>van</strong> Nieuwenhuizen. Supergravitywith the ordinary space transformation= 8,.re~”+ ~r8,.m + ~fiytmf// + A ~ (3)In order to do so, one identifies the parameters as followsL””’(O=O)=Am”. (4)Compatibility for the terms with ~“ and A tmfl is manifest, but for the terms in “ one finds(8,. ~1)Vam(0= 0) + ~a (8aV,im ~ = ytm~f; (5)Thus, V~m(0 = 0) = 0 and V,.tm = e,.m + ~ëy”i~j,. + . One must thus choosea gauge such that these resultshold. Whether this can be done in all order 0 cases considered below, has not been proven but seemsplausible.Repeating the same procedure for the gravitino, we have (see page 217)(AV,.i)= (8,.Er)V,~~+(8~E”)Va°+Er8rV,.a +Ea8aV,.ui +~(L. ~7)abIIIb(6)In this case, 8(sup)*,. must be equal to the 0 = 0 terms in (8,.Ea)V,.~~+ E~8V,.~ and one findsva”(0 = 0) = ~a ~ = ~a + ~ — ~,. )o” +... (7)where m~= —~(S+ iy5F — 2i,.4y5) and ~uses ,~and ~i instead of ~ and w)is the improved spin connection (the algebra simplifies if onema — ma( ,\_ mnp~~ ‘8(O~ —Ui,. l~C~I~I~J3 ~L p~m~to order 0, and finds hatm “ (0 = 0)= 0. The gauges VaA(0 = 0) = h~~(oSimilarlyone can find h,. = 0)= 0can always be implemented by choosing the order 0 parts of EA and A ma approximately.Since Va”(O = 0) = 6,,” and V,,m(0 = 0) = h,,m~(0= 0) = 0, one can require also compatibility for thesecomponents. One finds then to order 0 =0= 0 = (0a~”)~II,.” + (8,,E~)6fl°+ r8,.&r,a + ~8~V,,”+~Atmh2(OmflY~b6,,b. (9)Clearly one needs to know first the parameters to order 0, and then one can determine Vaa to order 0from (9).The superparameters to order 0’~’follow from the knowledge of the superparameters to order0k byrequiring compatibility of the parameter composition rules in ordinary space and in superspace. Insuperspace a symmetry operation with (E2A L2 m~)followed by an operation with (,E 1A, L1 tm~)minus14*2 yields again a symmetry operation with composite parameters
P. <strong>van</strong> Nieuwenhuizen, Supergravity 315fl_(~A 8 ~~II+~Z~II\_(14*2—12 ~2 A1 12 / I.L12 m~= (~A8Lmn + L ma) — (1 2). (10)2rn(L17a + S1L2Since we work in a special gauge, the superparameters will in general depend on em,., cu,.”, etc., and onemust take the variation of these fields as dictated by the ordinary space approach. This is indicated bythe symbol Si. In ordinary space the parameter composition law is as discussed in section 1 (pages 219, 220)= (~2r8,41TM+ ~e2y~ ’)— (14*2)~12 = (~2”8r l”+~A2mut(O.maEir— ~ 2y 1çb,. ) —(14*2) (11)A12 = (e2~8~Ama + A 2 mA ~ + AE2YTM 1Ui,. + ~j 2o.m~~(5 — iy5P)e1) —(14*2).Thus we need in ordinary space a closed algebra, and since this has only been achieved in second orderformalism, we use u = co(e, i/i).As a result one findsm11, theand superparameters solving these equations. to orderUsing 0 bythese equating order~12~(00 parameters, = 0) = ~12~(0 one can = 0) obtain andsimilarly the remaining for E12~and order 0L12 components of the supervielbein. The results are given in the following table:TableEM = ~ + E” = “ + ~iy”O,~r,,”— kA . ~~orL’”” = A’”” +vA_fe M+2Oy~—‘ 4~(&Y’”)rEv~A~’”” + lu”(S — iy~P)]~‘+l(c~,.o.—,3y,,)9In order to obtain parameters to order 02, one evaluates [42, 4i} on, say, the field V,.tm, and in ~24i V,.tmthe variation 42 not only acts on V,.tm as dictated by superspace but also on the fields of ordinary spaceaccording to 82. It is essential to consider always the full groups in superspace and ordinary space. Forexample, [A(E”), A(Lm’”)] is again a Lorentz rotation in superspace, but in ordinary space [Sfr~),5(A ma)] is a supersymmetry transformation.The general procedure is to obtain first the parameters to order 0~’from those to order 0”. ThenV,.” and h,.tm~ to order0k+1 follow from the superparameters to order 0” and V,,A and h,, m~followfrom the superparameters to order g1c+1~It is remarkable that in solving for the superparameters onefinds differential equations whose equations must satisfy certain fermionic integrability conditions. Theyalways do. Also, the superparameter solutions are not unique but contain arbitrary integrationconstants. For example, solving28a,~I — 1 8,,,~ = 2~2YTM~1 (12)the general solution is.ETM(0) = — ~iy~0+ ëOH,. + iy5OK,. + ~15~0L (13)with arbitrary H, K and L. We will discuss below an example of conformal superspace supergravity
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