254 P. <strong>van</strong> Nieuwenhuizen. Supergravitvof the quantum field equations (now also of the ghosts) as derived from the full quantum action. Forexample, two BRST transformations on the antighost C*a yield a result proportional to ~5(F 0y’3”) =F0,,R’7C” which is indeed proportional to 6.2~(qu)/6C*a.(Nilpotency is important in renormalizabletheories to analyze the higher order quantum correction.) It is not known whether such theories with 6and higher ghost-couplings exist, and, if they exist, whether one can eliminate these ghost couplings byintroducing auxiliary fields.2.9. Finiteness of quantum supergravity?Quantum supergravity is more finite as far as ultraviolet divergences are concerned than ordinarygeneral relativity. Since this subject has been discussed in detail at many conferences, we refer fordetails to these sources as well as the original literature. For a review, see ref. [286].The first breakthrough [512]occurred in the N = 2 model, where an explicit computation of theone-loop correction to photon—photon scattering revealed that all divergences in the process cancel. Atheoretical explanation was given [512], based on the observation that(i) graviton—graviton 2 and on-shellscattering Rh,. = 0. is finite because possible counter terms are of the form £2? =aR~,.+ (ii) Using /3R (global) supersymmetry of the S-matrix, one can “rotate” gravitons away and replace bygravitinos, etc. This then shows that all four-point processes are finite. (Higher point processes have alsobeen shown to be finite in this way.)Of course one must show that starting from graviton—graviton scattering one can indeed reach allother processes. This has been done.An alternative proof, valid for all n-point functions, was given [123]by showing that no £2? existson-shell which is invariant under the on-shell transformations of supergravity. In particular it was shownthat no £2? can start with gravitino terms but must start with R~,.2and R2. Not all details of this analysishave been published.At the two-loop level, again both proofs of finiteness have been used. Since the only bosonic £2?which does not <strong>van</strong>ish on-shell is given by [503]£2? = a~2R,,0R~,.”R~’3 (1)and describes helicity-ifipping of graviton—graviton scattering, whereas supersymmetry (global as well aslocal) conserves helicity, a =0. Hence, as before, graviton—graviton scattering is two-loop finite insupergravity, and rotating gravitons away and replacing them by other particles, one shows that also atthe two-loop level supergravity is finite [283].The counter term analysis has matched also this result byclaiming that one cannot extend £2? in (1) to a full on-shell supersymmetnc invariant [123].For N = 1 supergravity, the tensor calculus [189],or, equivalently, superspace methods [191]havesuperseded these proofs and prove one- and two-loop finiteness. In particular, the counter termanalysis was performed only to order 4,2, whereas the tensor calculus and superspace give completeresults with considerable less algebra. For N = 2 supergravity similar results have recently beenobtained.Possible problems (but no more than that!) arise at the three-loop level. Namely, it seems that in allN-extended pure supergravities on-shell a supersymmetric invariant three-loop counter term exists[1291.Whether it actually will have non<strong>van</strong>ishing coefficient is the big question. This £2? has in itsbosonic sector the Bel—Robinson tensor.
The Bel—Robinson tensor is defined byP. <strong>van</strong> Nicuwenhuizen, Supergravity 255T”’3”4 = R~~PAUR$P’4O. + *RaPAU *R$’4 + R*aPk~~R*$~’4~ + *R*aPAu *R*$’4 (2)where the stars denote left and right duals. Since *R*~ + Ra 0p,~,is proportional to R~,.— ~ and** = —1, it follows that on-shell (i.e., Ru,. + Ag,,,. = 0), left and right dual of the Riemann tensorcoincide. Also *R*‘~$ is on-shell proportional to the Einstein tensor. The B.R. tensor is symmetric inaf3, in ~ under pair exchange (a$) ~-* A~and on-shell it is conserved, Da Ta$A~~=0. (See the thesis ofL. Bel, for example.) If there is no cosmological constant A, one has on-shell that T~~0AMis completelysymmetric, traceless and conserved.It is now possible, either by the Noether procedure or (to all orders5to in Ka and full locally orders supersymmetricin ~fi,.~)by thetensor invariant. calculus, Thus, to at show the three that loop one can levelextend there the is a invariant £2’ for N T~03,8T”’3”’ = 1 supergravity on-shell which is on-shellinvariant under local supersymmetry and which poses a danger for the finiteness of supergravity.The crucial question whether N =8 supergravity is finite beyond two loops has been analyzed bymeans of superspace methods by Howe and Lindström. Just as for N = 1, 2, 3, 4 supergravity, alltorsions and curvatures are on-shell functions of only one superfield. For N = 1 this is a 3-spinor WABC(see section 5), for N = 2 a 2-spinor WAB, for N = 3 a one-spinor WA, for N = 4 a scalar W, while forN = 8 one has a scalar W,1k, where i, ..., 1 are SU(8) indices. Moreover, W,jkl is totally antisymmetricand self-dual. The 0 =0 components of W,Jk, represent the scalars in the N = 8 model after fixing thelocal SU(8) gauge (see section 6). The constraint D~,Wjk~m= öbAk~m1aputs W on-shell. These results arelinearizations of results obtained by Brink and Howe.The Weyl tensor C appears in W asD~D~D~D~Wmnpq~ (3)(In two-component notations, C is totally symmetric, see the appendix.) It is now easy to write down asupersymmetric invariantI = K~~Jd’~x ~ (4)2088h8where Note that g~,.= from y,.,’, (3) + Kh~,..Performing it follows that Wthe is dimensionless, 9-integration one so that endsone up finds with ainnon<strong>van</strong>ishing I a term of the product form of K Weyltensors (together with its supersymmetric extensions). Thus it would seem that N = 8 has non<strong>van</strong>ishingin<strong>van</strong>ants which could serve as infinities in the S-matrix from 7 loops onwards. Increased understandingof how to build invariant actions with measures d”8 where n
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