208 P. <strong>van</strong> Nieuwenhuizen. SupergrarirvS2’( 2) = ~1. ~‘ mncd (D,,e~)e ~ 800cdD ~ tm~1~ mn (3,.e,. — 0,,e,. w,, er,..Note that the derivative D,, always contains only the spin connection, but not a connection F~,..As aresult, D,.e’ is non-zero.Next we vary the spin connection in the Rarita—Schwinger action.82’312 = ‘ ~“~~(tl/yyut/i) (80)cd) (4)Since l/i,.y5y~u~dt//,, can be written as vector terms and axial vector terms by decomposing Y~O~cd(seeappendix A)l/i,.757,ArcdtIJ,, = ~tlJ,.yS(e~~yd — ed~yC)llI,,+ ~et~,, bcdml/i,.ymt/,,, (5)and since l/’,.ylydt/i,, is symmetric in p~and o- while ~,.y’~i/i,, is antisymmetric (see appendix C), we find82’3/2 = — 8 1. ~“ ncdm (~ym~, )en ~ cd (6)Comparison of eqs. (6) and (3) thus yieldstm,, — D~etm,.= ~- (çj~ytmç/i) (7)D,.efor the field equation of the spin connection. Due to our rewriting of 2’2 as in eq. (1), one can easilyread off this result, since in eq. (6) and in eq. (1) the two -symbols are in common.With the first tetrad postulate (which is really a definition of w(e)) that 0,.em~+w,.m~(e)—= 0, one can proceed to solve from eq. (7) the spin connection ~ itself. <strong>To</strong> this purpose itis useful to introduce the contorsion tensor K,.””’ byma — mtm( ~+ ma(0,. —00,. ~, K,.w,.rn~(e) = ~e~”(8,.e~~ — 8~e~,.) — ~ (8,.emv — Opem,.) — ~em”en~(8~e~,, — 8,,e,~,)e’,.. (8)With (7) and the first tetrad postulate, one finds0,.etm~+ wtm(e) (,~ v) 0K2- 9— Kr,,,,. = ~ tli,,y~tl/~. ( )This equation is solved in the same way as one solves in general relativity for F”,.~(g)in terms of ~that is to say, one considers the identity— K~~,.)+~ — iç,.m)+ ~ — Içptm) = 2K,.,,,~. (10)
P. <strong>van</strong> Nieuwenhuizen, Supergravitv 209Substituting (9), one arrives at~ ~/i)= ~ — ~,.ynl/im + ~rny,.ll’n). (ii)Using the second tetrad postulate, 8,.e~+ ,.a~ — F~,.e”~ = 0 one can obtain an expression for F”,.~from eq. (ii). In general one defines torsion as the antisymmetric part of F”,.~= ~(F~— F~,.). (12)Clearly, F”,.~— F~,.= —K,.”~+ K~a,.,so that the torsion is given byS”,.~= —~-(t/i,.y”çfi,,). (13)In a similar manner as in eq. (10), one can solve from D,.(w(e))e’ —~s~-* ii = 0 the dependence ofw~,b(e)on the tetrad field. (Another way is to solve directly the tetrad postulate 8,.etm,, + w,.m”(e)e~~ —= 0.) Putting this result together with eq. (ii), one finds~ i/i) = ~ — R,.mn + Rmn,.)R,.p,m = —8,.e~~+ 8~e,,,,.+ ~- çl’,.y~i/i~. (14)The symbol R,.,b.m is defined to be ~ similarly for the other two R-functions. Clearly, the spinconnection w~”’(e,t/i) is supercovariant, by which is meant that if one transforms it under localsupersymmetry transformations, then it contains no 8 terms. Indeed, the terms (—~8,.ë)y”i/i,.comingfrom 8(—8,.em~)cancel against the 8 terms from Oil’,.. The symbols R,.~.rnare supercovariant bythemselves. That the solution of SI/Ow = 0 is supercovariant is an accident. For example, in theextended supergravities this equality does not hold, see subsection 6.2.1.5. Flat supergravity with torsionIn Einstein—Cartan theory, the Hubert action has a well-known symmetry f d~xeR(e, w(e)+ r) =f d~xe[R(e, 00(e)) — T + 1. (rAA,. )2] under w,.”~’1.V~T’~~0)ab + r,.~thwith T,.”~’= — ~ba but further arbitrary.The proof is trivial if one writes the terms linear in r in R,.,~flb(w(e)+r) as D,.(w(e))rpab — p.~*-~ 71 sinceone may add a Christoffel connection to D,.r~~5(because it cancels anyhow in the curl) and having thusobtained the full covariant deriv,ative, one can partially integrate to obtain a total derivative.In supergravity a similar identity holds. It is a matter of a small computation to show that [207]2’~ 2~(e, w(e, ~/~)+r)+2’312(e, t/’, w(e, t/i)+ r)= 2’~2~(e, w(e, I/i)) + 2’312(e, i/i, w(e, t/J)) + ~-~--~ (r,,~~r”’~ — (TAA,.)2) + total derivative. (1)Since w(e, I/i) is an extremum of the action, terms linear in r cancel.
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