224 P. <strong>van</strong> Nieuwenhuizen, Supergravitvtransformations in flat space8B,.—~iy,.A, SA~cr~F , oFo”~F,.~ (2)into a total derivative, S2°=3,.[~F”~ëy,Jt+-Lky”cr . F ]. <strong>To</strong> show this, use the Bianchi identity~VPO8,F =0. The Noether current is thus given by —~o~F-y”A. Hence, we begin by adding theNoether term= ~ ~ Fy”A. (3)This ensures that the order ic°terms in 8(10 +1N) cancel,2)iy”i/f,.even in 1°and in curved fromspace.SB,. and SA in JN~Considerfirst <strong>To</strong>the order terms K, one of the has terms form ,cF2 coming . The fromMaxwell Se”,. = (K/action yields (K/2Xiy”l/i~)T,.~(B) while the Noethercoupling yields (K/2)l/i,.cr Fy”o- . F . The sum is equal to~uI \Iz~ _..i L I~a$4 kV~’#’Y5Y~ ~a rn4g,.~alSlSince, however, the second factor is identically zero, these variations cancel. (This identity can beproved by using that ~ antisymmetrized in (va/pcr) <strong>van</strong>ishes.)<strong>To</strong> ordcr K there are also K l/iAOA terms in 8(1°+ 1N)~From the Dirac action one finds5J1/2 = —e ~ ~ i/i(AØ°A)+~ ( y”/ia)Oty”1-T),.°A) ~ (Ay~cr”A)(2ëybl/i,.,,— 7,.l/iab). (5)The first term is clearly cancelled if one adds to Sit a new term SA = —(K/2)Ey . i/iA since this newvariation produces in 211(2 precisely the opposite. Clearly, quite generally terms in the v~zriedactionproportional to a field equation can always be cancelled by adding an extra term to the transformation lawof the field whose field equation appears. Using this observation,m is proportional we can to cancel the the gravitino last terms field in equation. eq. (5),since A Aymcr~I~A= second general ~ ~““Ay5y,~A mechanism and which *hI~z&yai/1bc= one uses 2y5R over and over again in the Noether method is theobservation that terms in the varied action with 3 can be cancelled by adding an extra term to the actionobtained by replacing 3,. by —i/i,., provided all gravitinos appear symmetrically in the end result. Forexample, the variation of B,. in the Noether coupling in eq. (3) yields~ ycr”~A8~ (ëy,3A) — ~(i~”y”A~t9a (ëy,.A) — 0,. (ëyait)]. (6)Partially integrating the first two terms, they are proportional to R” since Iy~ — 3 . i/i = ~ R and/i/i,. — 3,.y• i/i = ~y~3,.R”so that they are cancelled by an extra Si/i,.. But the last term is equal to~- (ii”y~AXa,.e)yaA + ~ (~“y”A)(ëy~3,.A) (7)and one clearly sees that the 3 terms can be cancelled by adding to the action ~(K 2I4Xl/i,.y,,AXi/i”y”A)since both gravitinos yield a 3,, variation and appear symmetrically.
P. <strong>van</strong> Nieuwenhuizen, Supergravity 225In this way one adds systematically new terms to action and transformation laws until one arrives at acompletely invariant action. There are general arguments that this iterative procedure must always stopexcept when there are spin 0 fields A present [202]; in that case the action can be infinite series in(KA) tm.The final result obtained in this way is given by2 —~F,.,F””—~,øA+~ çfr,.o .Fy”A+~—(çIi,.u”~y”AXi/i~y,,A)+~ K2(AAXAA)Sit = ~ Fco~~ , SB,. = — ~ëy,.A (8)Setm,. = ~- iymi/i,. Si/i,. = -~-D,. + ~- (~y5y”A)(g~,.+ o-,,,. )y~ .The spin connection in ØÀ contains only i/i-torsion, but no A-torsion. The symbol F~’ is thesupercovariant curlF~=8,.B~+~i/i,.y,A-,a4-*v. (9)The first suggestion that there should be an axial vector auxiliary field was due to this result [202].Clearly, the result for Si/i,. depends on the matter fields A and suggests replacing them by a new field A~.We know already from the gauge algebra that= i(D,. + ~A,.y5) + ~y,.(S — iy5P — iA~y5) (10)and hence one adds to the action the gauge action 2(gauge, e, i/i, 5, P, A,.) as well as a coupling+~~~y5yh1IA)A~. (11)Solving for A,,, and substituting the solution A,, =4 and A2 terms.—(31/8),c(Aysy,,A) back into the action and Si/i,., onereproduces Thus, in all theAsupersymmetric Maxwell—Einstein system, only A,. plays a role, but S and P do not.This is due to the fact that this system is superconformal invariant. As we shall see, A,. is the gauge fieldof chiral rotations. (In the example of the spin (0, 1/2) coupling, S and P do play a role.) The action canbe written in a suggestive manner as2=~2)+2’3/2_~1(S2+P2_A~j+21_~A(ø+~-1.4ys)A+~(~,.cr”~y”AXF~s +F~’)(12)SB,. = —~-iy11,A, Sit “‘so .Due to the auxiliary fields S, F, A,. one has only added matter terms to the action without changing the
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