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Course Notes - Department of Mathematics and Statistics

Course Notes - Department of Mathematics and Statistics

Course Notes - Department of Mathematics and Statistics

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• ¯x = Σn ix iN = 2174868 = 2.50χ 2 trend = [Σr i x i − R¯x] 2p(1 − p)[Σn i x 2 i − N ¯x2[1039 − 4.28 × 2.50] 2=0.49(1 − 0.49)[6530 − 868 × 2.50 2= 4.06• The Trend statistic has only 1 degree <strong>of</strong> freedom.• Look up 4.06 with 1 degree <strong>of</strong> freedom on computer.• We find the result is significant, so we can reject the null hypothesis.Accept the alternative that the proportion with severe diseasedecreases as income increases.Summary - OR/AR/RRFactor 2Factor 1 Level 1 Level 2 TotalLevel 1 w x r 1 = w + xLevel 2 y z r 2 = y + zc 1 = w + y c 2 = x + z n = w + x + y + z• RR = w/(w+x)y/(y+z)• AR = w/(w+x) - y/(y+z)• OR = w/xy/z = wzxy161

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