12.07.2015 Views

Course Notes - Department of Mathematics and Statistics

Course Notes - Department of Mathematics and Statistics

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Sample size = 10Consider the situation where the sample size is increased to 10.Here the mean is n × π = 10 × 0.11 = 1.1 <strong>and</strong> the st<strong>and</strong>arddeviation is √ n × π × (1 − π) = √ 10 × 0.11 × 0.89 = 0.99. nπ ±3 √ nπ(1 − π) = 1.1 ± 3 × 0.99 = -1.87 <strong>and</strong> 4.07. These values arenot between 0 <strong>and</strong> n = 10, therefore not appropriate to use normalapproximation to the binomial here (distribution is skewed).Sample size = 100Consider the situation where the sample size is increased to 100.83

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