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CT4860 STRUCTURAL DESIGN OF PAVEMENTS

CT4860 STRUCTURAL DESIGN OF PAVEMENTS

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value represents the characteristic cylinder compressive stress at the same<br />

conditions (table 2).<br />

Concrete quality<br />

B-value C-values<br />

B35<br />

B45<br />

B55<br />

C28/35<br />

C35/45<br />

C45/55<br />

Characteristic (95% probability of exceeding) cube<br />

compressive strength after 28 days for loading of<br />

short duration, fcc,k,o (N/mm 2 )<br />

35<br />

45<br />

55<br />

Table 2. Dutch concrete qualities used in road construction.<br />

Generally on heavily loaded plain concrete pavements, such as motorways<br />

and airport platforms, the concrete quality C35/45 is used. On lightly loaded<br />

plain concrete pavements (bicycle tracks, minor roads, etc.) mostly concrete<br />

quality C28/35 and sometimes C35/45 is applied. In reinforced concrete<br />

pavements mostly the concrete quality C28/35 is applied and sometimes the<br />

concrete quality C35/45.<br />

The concrete quality C45/55 is used for precast elements such as concrete<br />

blocks, tiles and kerbs.<br />

According to both the CEB-FIP Model Code 1990 (3) and the Eurocode 2 (4)<br />

the mean cube compressive strength after 28 days for loading of short<br />

duration (fcc,m,o) is equal to:<br />

fcc,m,o = fcc,k,o + 8 (N/mm 2 ) (1)<br />

For the structural design of concrete pavements the compressive strength is<br />

not very relevant. Much more important is the flexural tensile strength that is<br />

related to the tensile strength.<br />

For elastically supported concrete pavements, the mean tensile strength after<br />

28 days for loading of short duration (fct,m.o) is equal to:<br />

fct,m,o = 0.9 [1.05 + 0.05 fcc,m,o] = 0.9 [1.05 + 0.05 (fcc,k,o + 8)] (N/mm 2 ) (2)<br />

The mean tensile strength after 28 days for loading of long duration (fct,m,∞) is<br />

taken as 70% of the mean tensile strength for loading of short duration:<br />

fct,m,∞ = 0.7 · fct,m,o = 0.7 · 0.9 [1.05 + 0.05 fcc,m,o] =<br />

= 0.7 · 0.9 [1.05 + 0.05 (fcc,k,o + 8)] (N/mm 2 ) (3)<br />

The value of the mean tensile strength, for loading of long duration, to be used<br />

in design calculations (fct,d,∞) is obtained by means of equation 4:<br />

fct,d,∞ = 1.4 fct,m,∞/γm = 1.4 · 0.7 · 0.9 [1.05 + 0.05 (fcc,k,o + 8)]/1.2 (N/mm 2 ) (4)<br />

where: 1.4 = ‘correction factor’ for a better agreement of the calculated tensile<br />

strength with the values normally used in pavement engineering<br />

γm = 1.2 is the material factor for concrete under tension<br />

10

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