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CT4860 STRUCTURAL DESIGN OF PAVEMENTS

CT4860 STRUCTURAL DESIGN OF PAVEMENTS

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'<br />

4 y ( W − y)<br />

transverse edge: R = (20b)<br />

'2<br />

W<br />

where: L’ = slab span (mm) in the longitudinal direction<br />

W’ = slab span (mm) in the transverse direction<br />

X = distance (mm) of the point under consideration at the longitudinal<br />

edge to the nearest transverse edge minus 1/3 of the support<br />

length C<br />

y = distance (mm) of the point under consideration at the transverse<br />

edge to the nearest longitudinal edge minus 1/3 of the support<br />

length C<br />

The equations 17 to 19 make clear why nowadays relatively small concrete<br />

slabs are applied in plain concrete pavements, with horizontal dimensions<br />

smaller than about 5 m (roads) or 7.5 m (airports) respectively. For these slab<br />

dimensions the span of the slabs both in the longitudinal (L’) and the<br />

transverse (W’) direction is much smaller than the critical slab length lcrit,<br />

''<br />

resulting in reduced warping stresses σ (equation 19).<br />

3.3.4 Temperature gradient stresses (Dutch method)<br />

In the Netherlands originally VNC (Cement Industry Association) has<br />

developed an analytical design method for plain concrete pavements (11,12).<br />

Recently the method has been upgraded, and extended with continuously<br />

reinforced concrete pavements, by CROW (5).<br />

One has realized that the most critical point of the pavement structure is<br />

somewhere at an edge of the plain concrete slab or at a crack of the<br />

reinforced concrete slab. At the edges or cracks there is by definition a<br />

uniaxial stress situation in the concrete slab (only stresses parallel to the edge<br />

or crack and no stress perpendicular to the edge or crack). For the calculation<br />

of the temperature gradient stresses this means that only a concrete beam<br />

(with unit width) along the edge or crack needs to be taken into account and<br />

not an entire plain concrete slab or a whole part of the reinforced concrete<br />

pavement between two transverse cracks.<br />

In the case of a small positive temperature gradient ∆t the warping (upward<br />

displacement) of the concrete slab along the edge or crack is smaller than the<br />

compression (downward displacement) of the substructure (characterized by<br />

the modulus of substructure reaction k) due to the deadweight of the concrete<br />

slab. This implies that the concrete slab remains fully supported (figure 12<br />

left). The flexural tensile stress σt at the bottom of the concrete slab in the<br />

center of a slab edge or crack can then be calculated by means of the<br />

equation:<br />

h⋅∆t<br />

σ t = α E<br />

(21)<br />

2<br />

t<br />

28

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