Revista IC3 original 6° A

Un pasado de gloria, un presente de luz. Revista IC 6°A 2018
2.-
du
u 2 ± a 2 = ln (u + u2 ± a 2 ) + c
=
1
u 2 ± a du =
2
a sec u tan u
a 2 sec 2 u − 1 du
= a u 2 sec u tan u
sec 2 u − 1 du = a u 2 sec u tan u
−1 + 1 + tan 2 u du
= a u 2 sec u tan u
tan y
= a 1
ln |tan [arc sec
u2 = ln |
u 2 − a 2 + u
| = ln |
a
du = a ln|tan u + sec u |
u2 a u ]| + sec [arc sec 1 a u ]
u 2 − a 2 + u
| + c
a
3.-
du
a 2 − u = arc sen u 2 a + c
1
=
a 2 − u 2 du
a cos u
=
u 2 −sen 2 u + 1 = a cos u
u 2 −sen 2 u + 1
= a cos u
u 2 cos 2 u du = a cos u
u 2 cos u du
= a u 2 1 du = a u 2 1 u = a u 2 1 arc sen 1 a u = arc sen (u a )
= arc sen ( u a ) + c
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