Correction - Université du Maine
Correction - Université du Maine
Correction - Université du Maine
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1).<br />
∑<br />
1975 ∼ 1984 = 24000(1 + i) 9 + · · · + 24000(1 + i) + 24000<br />
= 24000[1 + (1 + i) + · · · + (1 + i) 9 ]<br />
= 24000 ×<br />
= 373447<br />
1 − (1 + i)10<br />
1 − (1 + i)<br />
TD 5<br />
Exercice 1<br />
Exercice 2<br />
Exercice 3<br />
V 1990 = ∑ 1975 ∼ 1984 × (1 + i) 6 = 643745<br />
2).<br />
⇒<br />
V 1990 = K 0 = a (1 + i)n − 1<br />
i<br />
n = ln(1+ K 0 i<br />
a )<br />
ln(1+i) = 20
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