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(c). TD 5 Mois Capital Amortissement Intérêt Mensualités restant dû constantes 1 K 0 = 1000 A 1 = 79.04 I 1 = iK 0 = 9.5 88.54 = A 1 + I 1 2 K 1 = K 0 − A 1 A 2 = a − I 2 I 2 = iK 1 = 8.75 88.54 = A 2 + I 2 = 920.96 = 79.79 . . 11 K 10 = 175 A 11 = 86.88 I 11 = 1.6625 88.54 Exercice 1 Exercice 2 Exercice 3
(c). TD 5 Mois Capital Amortissement Intérêt Mensualités restant dû constantes 1 K 0 = 1000 A 1 = 79.04 I 1 = iK 0 = 9.5 88.54 = A 1 + I 1 2 K 1 = K 0 − A 1 A 2 = a − I 2 I 2 = iK 1 = 8.75 88.54 = A 2 + I 2 = 920.96 = 79.79 . . 11 K 10 = 175 A 11 = 86.88 I 11 = 1.6625 88.54 12 K 11 = 88.12 A 12 = 87.7 I 12 = 0.8371 88.54 Exercice 1 Exercice 2 Exercice 3
Page 1 and 2: TD 5 Exercice 1 Exercice 2 Outils d
Page 3 and 4: Excercice 1 Rappel : A p, p eme amo
Page 5 and 6: [ (1+i) n −1 ] 2). K 0 = A 1 i av
Page 7 and 8: [ (1+i) n −1 ] 2). K 0 = A 1 i av
Page 9 and 10: Excercice 2 TD 5 Exercice 1 Exercic
Page 11 and 12: 1). ∑ 1975 ∼ 1984 = 24000(1 + i
Page 13 and 14: Excercice 3 1). 1 er méthode : le
Page 15 and 16: (c). Mois Capital Amortissement Int
Page 21 and 22: TD 5 2). 2 eme méthode : le taux m
Page 23: (c). TD 5 Mois Capital restant dû
Page 27: TD 5 Exercice 1 Exercice 2 Exercice

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