Correction - UniversitÃ© du Maine

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Excercice 1 Rappel : A p, p eme amortissement ; i, taux ; K 0 , capital emprunté ; a, annuité ; K p, le capital restant dû à la fin de p eme amortissement. ◮ A p = A 1 (1 + i) p−1 [ ◮ (1+i) n −1 ] K 0 = A 1 i ◮ a = ◮ A 1 = K 0 i 1−(1+i) −n a (1+i) n ⇔ a = A 1 (1 + i) n ◮ K p = K 0 − ∑ p k=1 A k = K 0 (1+i) n −(1+i) p (1+i) n −1 TD 5 Exercice 1 Exercice 2 Exercice 3 1). n = 10, A 3 = 2103.70, A 6 = 2453.30 A p+1 = A p(1 + i) Si les annuités sont constantes, les amortissement sont en progression géométrique de raison (1 + i) =⇒ A 3 = A 1 (1 + i) 2 A 6 = A 1 (1 + i) 5 √ ⇒ A 6 = (1+i)5 A 3 (1+i) 2 = (1 + i) 3 ⇒ i = 3 A6 − 1 = 0.0526 A 3
[ (1+i) n −1 ] 2). K 0 = A 1 i avec A1 = A 3 (1 + i) −2 ⇒ K 0 = A 3 (1 + i) −2[ (1 + i)n − 1 ] i = 24173.51 TD 5 Exercice 1 Exercice 2 Exercice 3
Page 1 and 2: TD 5 Exercice 1 Exercice 2 Outils d
Page 3: Excercice 1 Rappel : A p, p eme amo
Page 7 and 8: [ (1+i) n −1 ] 2). K 0 = A 1 i av
Page 9 and 10: Excercice 2 TD 5 Exercice 1 Exercic
Page 11 and 12: 1). ∑ 1975 ∼ 1984 = 24000(1 + i
Page 13 and 14: Excercice 3 1). 1 er méthode : le
Page 15 and 16: (c). Mois Capital Amortissement Int
Page 21 and 22: TD 5 2). 2 eme méthode : le taux m
Page 23 and 24: (c). TD 5 Mois Capital restant dû
Page 25 and 26: (c). TD 5 Mois Capital Amortissemen
Page 27: TD 5 Exercice 1 Exercice 2 Exercice

Correction - UniversitÃ© du Maine

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