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(c). Mois Capital Amortissement Intérêt Mensualités restant dû constantes 1 K 0 = 1000 A 1 = 78.85 I 1 = iK 0 = 10 88.85 = A 1 + I 1 2 K 1 = K 0 − A 1 A 2 = a − I 2 I 2 = iK 1 = 9.21 88.85 = A 2 + I 2 = 921.15 = 79.64 . . TD 5 Exercice 1 Exercice 2 Exercice 3 11 K 10 = 173.23 A 11 = 87.12 I 11 = 1.73 88.85 12 K 11 = 86.4 A 12 = 87.99 I 12 = 0.864 88.85
(c). Mois Capital Amortissement Intérêt Mensualités restant dû constantes 1 K 0 = 1000 A 1 = 78.85 I 1 = iK 0 = 10 88.85 = A 1 + I 1 2 K 1 = K 0 − A 1 A 2 = a − I 2 I 2 = iK 1 = 9.21 88.85 = A 2 + I 2 = 921.15 = 79.64 . . TD 5 Exercice 1 Exercice 2 Exercice 3 11 K 10 = 173.23 A 11 = 87.12 I 11 = 1.73 88.85 12 ∑ K 11 = 86.4 A 12 = 87.99 I 12 = 0.864 88.85 K 0 − ∑ ∑ ∑ ∑ K i = 0 Ap = K 0 Ip = 66.2 ap = 1066.2 i.e., K p = K 0 (1 + i) n − (1 + i) p (1 + i) n − 1 ⇓ K 10 = K 0 (1 + i) 12 − (1 + i) 10 (1 + i) 12 − 1 = 173.23
Page 1 and 2: TD 5 Exercice 1 Exercice 2 Outils d
Page 3 and 4: Excercice 1 Rappel : A p, p eme amo
Page 5 and 6: [ (1+i) n −1 ] 2). K 0 = A 1 i av
Page 7 and 8: [ (1+i) n −1 ] 2). K 0 = A 1 i av
Page 9 and 10: Excercice 2 TD 5 Exercice 1 Exercic
Page 11 and 12: 1). ∑ 1975 ∼ 1984 = 24000(1 + i
Page 13 and 14: Excercice 3 1). 1 er méthode : le
Page 15 and 16: (c). Mois Capital Amortissement Int
Page 17: (c). Mois Capital Amortissement Int
Page 21 and 22: TD 5 2). 2 eme méthode : le taux m
Page 23 and 24: (c). TD 5 Mois Capital restant dû
Page 25 and 26: (c). TD 5 Mois Capital Amortissemen
Page 27: TD 5 Exercice 1 Exercice 2 Exercice

Correction - UniversitÃ© du Maine

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