Correction - Université du Maine
Correction - Université du Maine
Correction - Université du Maine
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[ (1+i)<br />
n −1 ]<br />
2). K 0 = A 1 i avec A1 = A 3 (1 + i) −2<br />
⇒<br />
K 0 = A 3 (1 + i) −2[ (1 + i)n − 1 ]<br />
i<br />
= 24173.51<br />
3).<br />
TD 5<br />
Exercice 1<br />
Exercice 2<br />
Exercice 3<br />
4).<br />
K p = K 0 −<br />
a =<br />
K 0 i<br />
1 − (1 + i) −n<br />
=<br />
2417.51 × 0.0526<br />
1 − (1.0526) −10<br />
= 3170.23<br />
p∑<br />
k=1<br />
A k = K 0<br />
(1 + i) n − (1 + i) p<br />
(1 + i) n − 1
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