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Laju Reaksi - e-Learning Sekolah Menengah Kejuruan

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t = 70 0 C n = 2 ; t 0 = 30 0 C n = 0<br />

t =<br />

n<br />

1 <br />

x 3 menit =<br />

3 <br />

2<br />

1 <br />

3 <br />

x 3 menit =<br />

3<br />

1 menit<br />

7. <strong>Reaksi</strong>: A + B hasil<br />

<strong>Laju</strong> reaksi berbanding langsung dengan hasil perkalian konsentrasi zat<br />

yang bereaksi.<br />

- Jika [B] tetap, maka penambahan [A] menyebabkan penambahan laju<br />

reaksi yang sebanding, artinya jika [A] laju reaksi = 2 x lebih besar.<br />

V = k [A] 2 , jika [B] tetap<br />

- Jika [A] tetap, [B] = 2; [B] v = k’[B] 2<br />

Pada awal [A] = 2 [A]; [B] = 2 ; [B] laju reaksinya = 8 x lebih besar,<br />

berati laju reaksi v = k’ [A] [B] 2<br />

8. v = k [P] 2 [Q]<br />

v = [3] 2 [3] 1 v = 9 x 3 = 27 kali<br />

9. Dari persamaan laju v = k [NO] 2 [H 2 ].<br />

a. k =<br />

5<br />

2,6x10<br />

3<br />

(6,4x10<br />

)(2,2x10<br />

3<br />

)<br />

= 288,5 M -2 . det -1<br />

b. Persamaan laju reaksi: v = 288,5 (NO] 2 [H 2 ]<br />

= 288,5 (0,5) 2 (0,5) = 36,06 M.det -1<br />

10. v = k [A] 2 [B]<br />

= k {2 [A] } 2 {[B]}<br />

= k 4 [A] 2 2 [B]<br />

= 8 k [A] 2 [B]<br />

Jadi laju reaksi lebih cepat 8x dari semula.<br />

Kim. 10. <strong>Laju</strong> <strong>Reaksi</strong> 46

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