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Diffrazione - Consorzio Elettra 2000

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<strong>Diffrazione</strong> da KE<br />

Attenuazione Supplementare (1/3)<br />

E 0 (R) = campo che si avrebbe in assenza dellostacolo:<br />

E 0<br />

(R) = j!<br />

2"<br />

# A # e$ j! ( a+b)<br />

ab<br />

+% +%<br />

&<br />

&<br />

$% $%<br />

e<br />

a+b<br />

$ j!<br />

2ab x2 + y 2<br />

( ) dx dy<br />

Attenuazione supplementare L S<br />

j!<br />

L S<br />

= E 0<br />

E = 2"<br />

j!<br />

2"<br />

# A # e$ j! ( a+b)<br />

ab<br />

# A #<br />

e$ j! ( a+b)<br />

ab<br />

+% +%<br />

&<br />

&<br />

$% $%<br />

+% +%<br />

&<br />

$%<br />

&<br />

h<br />

e<br />

e<br />

a+b<br />

$ j!<br />

2ab x2 + y 2<br />

a+b<br />

$ j!<br />

2ab x2 + y 2<br />

( ) dx dy<br />

( ) dx dy<br />

=<br />

+%<br />

&<br />

$%<br />

+%<br />

&<br />

h<br />

a+b<br />

$ j!<br />

2ab<br />

e x2 dx<br />

a+b<br />

$ j!<br />

2ab<br />

e x2 dx<br />

L S<br />

=<br />

+$<br />

%<br />

2 ! e<br />

+$<br />

%<br />

h<br />

0<br />

a+b<br />

" j#<br />

2ab x2 dx<br />

a+b<br />

" j#<br />

2ab<br />

e x2 dx

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