andrzej kanicki, jerzy kozłowski stacje ... - ssdservice.pl

A. Kanicki, J. Kozłowski: STACJE ELEKTROENERGETYCZNE
= 68⋅10
9
⎡
⎛ 3923
⋅ ⎢0,3
+ 0,7 ⋅sin⎜
6
⎣
⎝ 587 ⋅10
⋅5⋅10
Współczynnik sztywności
⎞⎤
⎟⎥
= 2.674 ⋅10
⎠⎦
⎡ N
⎢
⎣m
o
10
⋅90
− 7
2
⎤
⎥
⎦
N
−20
1 1
= +
S ⋅ l n ⋅ E
s−20
⋅ s
=
10
5
1
+
⋅ 36.7 2.832 ⋅10
10
1
⋅ 587 ⋅10
−6
= 3.326 ⋅10
−7
⎡
⎢
⎣
1
N
⎤
⎥
⎦
N
60
1
= +
S ⋅ l
1
n ⋅ E
s 60
⋅ s
=
10
5
1
+
⋅ 36.7
2.674 ⋅10
10
1
⋅ 587 ⋅10
−6
= 3.362 ⋅10
−7
⎡
⎢
⎣
1
N
⎤
⎥
⎦
Współczynnik ζ
ζ
ζ
( n ⋅ g ⋅ m ⋅l) ( 9.80665⋅1.98⋅36.7)
2
2
− 20 =
=
3 3
−7
24⋅
F st 20 ⋅ N 20 24⋅
4903 ⋅3.326⋅10
=
− −
( n ⋅ g ⋅ m ⋅ l) ( 9.80665⋅1.98⋅36.7)
2
2
60 =
=
3 3
−7
24⋅
F st 60 ⋅ N60
24⋅3923
⋅3.362⋅10
=
Kąt wychylenia przewodów na końcu zwarcia
T k 1 0.5
= = 0.5443 0.5
T 0.9186
>
res−20
δ k −20
= 2⋅δ
1 = 2⋅71.3
= 142.6
5
o
1.043
0,5396
T
T
k1
res 60
=
0.5
1.027
= 0.4868 ≤ 0.
δ
⎡
o
1 cos 360
k1
k 60 = δ1
⋅ ⎢ − ⋅ ⎥ = 71.3⋅
1 cos 360 =
T
⎢ − ⎜ ⋅ ⎟
res 60
1.027
⎥
⎢ ⎜
⎟⎥
⎝ ⎠
⎣
⎛
⎜
⎝
Maksymalny kąt wychylenia przewodów podczas zwarcia
T
⎞⎤
⎟
⎠⎦
⎡
⎣
⎛
0.5
⎞⎤
⎦
142.4
o
o
k 20 = 142.6 >
δ − 90
= 1−
r = 1−
2.954 = 1. 954
χ − 20 −
δm − 20 =
δ
k 60
180
o
= 142.4
o
≤ 90
o
o
Strona 168 z 302