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A. Kanicki, J. Kozłowski: STACJE ELEKTROENERGETYCZNE Linia AAA: F = max Linia BBB: F = max { F ;F } = max{ 16350;17310} = 17310 [ N] 1765 [ kG] Linia BBB, 1-sza bramka: F = max Szyna zbiorcza 220 kV: F = max Szyna zbiorcza I 110 kV: F = max Szyna zbiorcza II 110 kV: F = max f t = { F ;F } = max{ 14390; 15890} = 15890 [ N] 1620 [ kG] f t = { F ;F } = max{ 9206;11290} = 11290 [ N] 1151[ kG] f t = { F ;F } = max{ 10400;12510} = 12510 [ N] 1276 [ kG] f t = { F ;F } = max{ 6630;10490} = 10490 [ N] 1070 [ kG] f t = { F ;F } = max{ 6064; 6818} = 6818 [ N] 695 [ kG] f t = Siła naciągu uchwytów przewodów Szyny 220 kV Fk = 1.5 ⋅ Fmx = 1.5 ⋅17.31 = 26.0 [ kN] Szyny 110 kV Fk = 1.5 ⋅ Fmx = 1.5 ⋅10.49 = 15.7 [ kN] Poziome wychylenie przewodów Obliczenia dla 220 kV: −7 ( F − F ) = 3.362⋅10 ⋅( 14990− 3923) 0. 003721 εela = N ⋅ t st = T T = 0.5 s ≥ 4 1.027 = 4 res k 1 = 2 0.2568 s ⎛ I T 40000 1.027 c k3 ⎞ res −18 ⎛ ⎞ εth = th ⋅⎜ ⎟ ⋅ = 0.27 ⋅10 ⋅⎜ ⎟ ⋅ = 0.000322 ⎝ n ⋅s ⎠ 4 ⎝ 0.000587⎠ 4 2 Strona 170 z 302
A. Kanicki, J. Kozłowski: STACJE ELEKTROENERGETYCZNE C 2 2 ⎞ 3 ⎛ 36.7 ⎞ D = ⎟ ⋅ ela th ⎜ ⎟ = c 8 ⎝ 0.8334 ⎠ 3 ⎛ l 1+ ⋅ 8 ⎜ ⎝ b r = 2.954 ≥ 1.8 C F = 1.15 δ o m = 180 ≥ δ1 = Obliczenia dla szyn 110 kV: ⎠ 71.30 b 1 ( ε + ε ) = 1+ ⋅ ⋅ ( 0.003721 + 0.000322 ) 1. 985 o h = CF ⋅CD ⋅ bc ⋅sinδ = 1.15⋅1.985⋅0.8334⋅sin 71.30 = −7 ( F − F ) = 7.780⋅10 ⋅( 9983− 3923) 0. 004715 εela = N ⋅ t st = T T = 0.5 s ≥ 4 0.3204 = 4 res k 1 = 2 0.0.0801s o ( ) 1.983 [ m] ⎛ I T 40000 0.3204 c k3 ⎞ res −18 ⎛ ⎞ εth = th ⋅⎜ ⎟ ⋅ = 0.27⋅10 ⋅⎜ ⎟ ⋅ = 0.000100 ⎝ n ⋅s ⎠ 4 ⎝ 0.000587⎠ 4 2 C 2 2 ⎞ 3 ⎛ 14 ⎞ D = ⎟ ⋅ ela th ⎜ ⎟ = c 8 ⎝ 0.1213 ⎠ 3 ⎛ l 1 + ⋅ 8 ⎜ ⎝ b ⎠ ( ε + ε ) = 1 + ⋅ ⋅ ( 0.004715 + 0.0001) 5. 007 r = 4.768 ≥ 1.8 C F = 1.15 δ o m = 180 ≥ δ1 = 78.15 b 1 o h = CF ⋅CD ⋅ bc ⋅sinδ = 1.15⋅5.007⋅0.1213⋅sin 78.15 = o ( ) 0.6834 [ m] Poziome wychylenie przewodów podczas zwarcia wyznacza się jedynie dla temperatury obliczeniowej 60 o C. Minimalny odstęp izolacyjny występujący pomiędzy przewodami podczas zwarcia Obliczenia dla szyn 220 kV: a min = a − 2 ⋅ b h = 3.5 − 2 ⋅1.983 = −0.4655 [ m] Warunek: amin = −0.4655 > adop = 1.85 Strona 171 z 302
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ANDRZEJ KANICKI, JERZY KOZŁOWSKI S
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