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Read Back Signals in Magnetic Recording - Research Group Fidler

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Numerical Methods<br />

Aij = ∫ σ() r ∇ϕ j () r ∇ϕi()<br />

r dV , (4.13)<br />

V<br />

si =−∫s() r ϕi()<br />

r dV , (4.14)<br />

V<br />

∂u()<br />

r<br />

bi = ∫ σ() r ∇u() r ϕ i() r dA= ∫ σ() r ϕi()<br />

r dA<br />

∂n<br />

� � (4.15)<br />

∂V ∂V<br />

(4.12) can be written as<br />

N<br />

∑ Au ij j<br />

j=<br />

1<br />

= bi + si = ri<br />

. (4.16)<br />

Here the system matrix A = ( Aij<br />

) is symmetric and positive def<strong>in</strong>ite. s i is the source term,<br />

and b i is due to boundary conditions and only contributes, if the i-th node is situated at the<br />

surface ∂ V ( r i ∈∂V<br />

). In this case we have to determ<strong>in</strong>e the <strong>in</strong>tegral <strong>in</strong> (4.15) by tak<strong>in</strong>g<br />

boundary conditions <strong>in</strong>to account. Here we have to dist<strong>in</strong>guish between Dirichlet and<br />

Neumann boundary conditions. r i denotes the right hand side and is the sum of the boundary<br />

and the source term.<br />

4.1.1 Dirichlet Boundary Conditions<br />

In case of Dirichlet boundary conditions the value of the i-th node u( r ) = b is known. So the<br />

whole i-th equation can be replaced by<br />

i i<br />

ui = bi.<br />

(4.17)<br />

This would destroy the symmetry of the matrix A ij . To ma<strong>in</strong>ta<strong>in</strong> its symmetry, which is<br />

convenient for solv<strong>in</strong>g a system of l<strong>in</strong>ear equations, the matrix entry A ii is just multiplied by a<br />

6<br />

large number ( ~10 ). Then the right hand side is set to b i multiplied with the new coefficient<br />

A ii .<br />

4.1.2 Neumann Boundary Conditions<br />

In case of Neumann boundary conditions the normal component of σ() r ∇u()<br />

r , that is<br />

n⋅σ() r ∇ u() r =− j()<br />

r , is given at the boundary of the mesh. Here j() r can be <strong>in</strong>terpreted as a<br />

44

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