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Read Back Signals in Magnetic Recording - Research Group Fidler

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Numerical Methods<br />

with<strong>in</strong> the volume V. Outside the magnetic field H 1 is set to zero<br />

out<br />

H 1 = 0 . (4.54)<br />

Then the boundary condition writes as<br />

∂H<br />

∂n<br />

<strong>in</strong><br />

1<br />

=− n× j<br />

∂V<br />

. (4.55)<br />

Now H 1 can be calculated with<strong>in</strong> the volume V as described <strong>in</strong> Section 4.1. The source term<br />

is determ<strong>in</strong>ed by<br />

∫<br />

s = curl jϕ ( r ) dV . (4.56)<br />

i i<br />

V<br />

Here the source term is a vector. Each component refers to one of the three Poisson equations<br />

<strong>in</strong> (4.53). Partial <strong>in</strong>tegration gives<br />

si = � ∫ n× jϕi() r dA − ∫j×<br />

grad ϕi()<br />

r dV . (4.57)<br />

∂V<br />

V<br />

The boundary <strong>in</strong>tegral becomes<br />

<strong>in</strong><br />

∂H1<br />

bi = ∫ ϕ i() r dA =− × ϕi()<br />

dA<br />

∂ ∫ n j r<br />

n<br />

� � . (4.58)<br />

∂V ∂V<br />

So the first <strong>in</strong>tegral <strong>in</strong> the source term and the boundary term cancel each other. The right<br />

hand side is therefore<br />

∫<br />

r =− j× grad ϕ(<br />

r ) dV . (4.59)<br />

i i<br />

V<br />

The gradient of the test function and the current density are constant for each tetrahedron, so<br />

the <strong>in</strong>tegral (4.59) can be calculated as sum over all tetrahedrons, which are enclosed to the<br />

i-th node.<br />

The second part H 2 has to fulfill<br />

and further<br />

Δ H = 0, Δ H = 0<br />

(4.60)<br />

<strong>in</strong> out<br />

2 2<br />

53

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