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The Locomotive - Lighthouse Survival Blog

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54 THE LOCOMOTIVE. [APHIL r<br />

Finding" of the Areas of Irregular Figures.<br />

We have received the following communication from Mr. Thomas L. Hadley of<br />

Woonsocket, concerning the determination of the areas of irregular figures :<br />

" I notice that<br />

you say in <strong>The</strong> <strong>Locomotive</strong> for January, 1890, that ' the most satisfactory way to calculate<br />

the area of a segment is that given in <strong>The</strong> <strong>Locomotive</strong> for December, 1886. This,<br />

method is exact, but it requires the engineer or inspector to have the table with him<br />

whenever he wishes to calculate a segment/<br />

Here is another method for finding the area<br />

Fig. 1. — Area op a Segment.<br />

of a segment. It is not original with me,<br />

however. I believe that the idea came from<br />

France, where it was used to find the average-<br />

pressure of an indicator card. I have ap-<br />

plied it also to the determination of the<br />

areas of segments and of irregular figures.<br />

Suppose, for example, Ave consider a boiler<br />

6G inches in diameter, in which the upper<br />

row of tubes is 26 inches from the top of the<br />

shell. Suppose we allow 3 inches out for<br />

the flange to support, and 2 inches out for<br />

the tubes to support.. This leaves a segment<br />

21 inches high, of a circle 60 inches in di-<br />

ameter. To determine the area of this segment,<br />

first draw a diagram of the boiler on<br />

a scale of one inch to the foot, as shown in<br />

Fig. 1. <strong>The</strong>n find the area of the whole head of the 66-inch boiler. Divide this by 2 T<br />

which gives the area of half the head. Bisect Fig. 1, as shown by the horizontal<br />

diameter, as only half of the diagram is needed to do the problem. Now cut out the<br />

upper half of the diagram carefully, and weigh it. This piece in the diagram I send<br />

Figs. 2 and 3.— Area of a Segment.<br />

you, weighed 12.3 grains. <strong>The</strong>n cut out the<br />

segment from this piece, and weigh that<br />

also. You will find that the segment<br />

weighs 6.35 grains. <strong>The</strong>n make a propor-<br />

tion as follows:<br />

12.3:6.35 :: 1710.6 (area of half the<br />

head): 883.1<br />

From which we conclude that the area of the segment is 883. 1 square inches.<br />

"<strong>The</strong> area and average pressure of an indicator diagram may be found in the same

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