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LR Rabiner and RW Schafer, June 3

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DRAFT: L. R. <strong>Rabiner</strong> <strong>and</strong> R. W. <strong>Schafer</strong>, <strong>June</strong> 3, 2009<br />

8.2. HOMOMORPHIC SYSTEMS FOR CONVOLUTION 435<br />

To represent signals as sequences, rather than in the z-transform domain<br />

as in Figure 8.8, the characteristic system can be represented as depicted in<br />

Figure 8.9 where the log function is surrounded by the z-transform operator <strong>and</strong><br />

its inverse. Similarly, the inverse of the characteristic system can be represented<br />

as in Figure 8.10. Figures 8.5 <strong>and</strong> 8.6 are special cases for Figures 8.9 8.10<br />

−1<br />

D∗<br />

{ }<br />

+ + + • • *<br />

Z { } exp{<br />

} -1<br />

yn ˆ[ ]<br />

Yˆ Z { }<br />

( z)<br />

Y( z)<br />

yn [ ]<br />

yˆ 1[<br />

n]<br />

∗ yˆ<br />

2[<br />

n]<br />

y1[ n]<br />

∗ y2[<br />

n]<br />

Figure 8.10: Representation of the inverse of the characteristic system for homomorphic<br />

deconvolution.<br />

respectively for the special case z = e jω , i.e., when the z-transform is evaluated<br />

on the unit circle of the z-plane.<br />

The z-transform representation is especially useful for theoretical analysis<br />

where the z-transform polynomials <strong>and</strong> rational functions can be more easily<br />

manipulated than DTFT expressions. This is illustrated in Section 8.2.3. Furthermore,<br />

as discussed in Section 8.4.2, if a powerful root solver is available, the<br />

z-transform representation is the basis of a method for computing the complex<br />

cepstrum.<br />

8.2.3 Properties of the complex cepstrum<br />

The general properties of the complex cepstrum can be illustrated by considering<br />

the case of signals that have rational z-transforms. The most general form that<br />

is necessary to consider is<br />

X(z) =<br />

=<br />

<br />

Mi<br />

A<br />

k=1<br />

(1 − akz −1 Mo<br />

)<br />

<br />

(1 − b −1<br />

k=1<br />

Ni <br />

(1 − ckz −1 )<br />

k=1<br />

k=1<br />

k=1<br />

k z−1 )<br />

z −Mo Mo <br />

A (−b −1<br />

k )<br />

Mi <br />

(1 − akz −1 Mo <br />

) (1 − bkz)<br />

Ni <br />

(1 − ckz −1 )<br />

k=1<br />

k=1<br />

(8.19)<br />

where the magnitudes of the quantities, ak, bk, <strong>and</strong> ck are all less than 1. Thus,<br />

the terms (1 − akz −1 ) <strong>and</strong> (1 − ckz −1 ) correspond to zeros <strong>and</strong> poles inside the

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