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NEAR OPTIMAL BOUNDS IN FREIMAN'S THEOREM

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CALDERÓN <strong>IN</strong>VERSE PROBLEM ON RIEMANN SURFACES 111<br />

Indeed, since a vanishes to large order at all boundary critical points of ψ, we may<br />

write<br />

<br />

χ(e 2iψ/h + e −2iψ/h )V |a| 2 dvg<br />

M0<br />

= h<br />

<br />

〈d(e<br />

2i M0<br />

2iψ/h − e −2iψ/h ),dψ〉V χ|a|2<br />

dvg<br />

|dψ| 2<br />

=− h<br />

<br />

(e<br />

2i M0<br />

2iψ/h − e −2iψ/h <br />

)divg V χ|a|2<br />

|dψ| 2 ∇g <br />

ψ dvg<br />

+ h<br />

<br />

(e<br />

2i<br />

2iψ/h − e −2iψ/h )V |a|2<br />

|dψ| 2 ∂νψ dvg.<br />

∂M0<br />

For the interior integral, we use Lemma 5.4 to conclude that<br />

− h<br />

<br />

(e<br />

2i M0<br />

2iψ/h − e −2iψ/h <br />

)divg V χ|a|2<br />

|dψ| 2 ∇g <br />

ψ dvg = o(h),<br />

and for the boundary integral we write ∂M0 = Ɣ0 ∪ Ɣ and observe that on Ɣ0, ψ = 0,<br />

so (e2iψ/h−e−2iψ/h ) = 0, while on Ɣ we have V = 0 from the boundary determination<br />

proved in Proposition A.1 of the appendix. Therefore,<br />

<br />

χ(e 2iψ/h + e −2iψ/h )V |a| 2 dvg = o(h),<br />

M0<br />

and the proof is complete. <br />

6. Inverse scattering<br />

We first obtain, as a trivial consequence of Theorem 1.1, a result about inverse<br />

scattering for asymptotically hyperbolic (AH) surfaces. Recall that an AH surface<br />

is an open complete Riemannian surface (X, g) such that X is the interior of a<br />

smooth compact surface with boundary ¯X, and for any smooth boundary-defining<br />

function x of ∂ ¯X, ¯g := x 2 g extends as a smooth metric to ¯X, with curvature tending<br />

to −1 at ∂ ¯X. IfV ∈ C ∞ ( ¯X) and if V = O(x 2 ), then we can define a scattering<br />

map as follows (see [20], [13] or[14]). First, the L 2 kernel kerL 2(g + V ) is<br />

a finite-dimensional subspace of xC ∞ ( ¯X) and in one-to-one correspondence with<br />

E := {(∂xψ)| ∂ ¯X; ψ ∈ kerL 2(g + V )}, where ∂x := ∇ ¯g x is the normal vector field to<br />

∂ ¯X for ¯g. Then, for f ∈ C ∞ (∂ ¯X), there exists a function u ∈ C ∞ ( ¯X), unique modulo<br />

kerL 2(g + V ), such that (g + V )u = 0 and u| ∂ ¯X = f . Then one can see that the<br />

scattering map S : C ∞ (∂ ¯X) → C ∞ (∂ ¯X)/E is defined by Sf := ∂xu| ∂ ¯X. We thus<br />

obtain the following.

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