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Fundamental Astronomy

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468<br />

Answers to Exercises<br />

6.2 a = 1.4581 AU, v ≈ 23.6kms −1 .<br />

6.3 The period must equal the sidereal rotation period<br />

of the Earth. r = 42,339 km = 6.64 R⊕. Areas<br />

within 8.6 ◦ from the poles cannot be seen from geostationary<br />

satellites. The hidden area is 1.1% of the<br />

total surface area.<br />

6.4 ρ = 3π/(GP 2 (α/2) 3 ) ≈ 1400 kg m −3 .<br />

6.5 M = 90 ◦ , E = 90.96 ◦ , f = 91.91 ◦ .<br />

6.6 The orbit is hyperbolic, a = 3.55 × 10 7 AU,<br />

e = 1 + 3.97 × 10 −16 , rp = 2.1 km. The comet will hit<br />

the Sun.<br />

6.7 The orbital elements of the Earth calculated from<br />

Table C.12 are a = 1.0000, e = 0.0167, i = 0.0004◦ ,<br />

Ω =−11.13◦ , ϖ = 102.9◦ , L = 219.5◦ . The geocentric<br />

radius vector of the Sun in the ecliptic coordinates<br />

is<br />

⎛ ⎞<br />

0.7583<br />

⎜ ⎟<br />

r = ⎝0.6673⎠<br />

.<br />

0.0<br />

The corresponding equatorial radius vector is<br />

⎛ ⎞<br />

0.7583<br />

⎜ ⎟<br />

r = ⎝0.6089⎠<br />

,<br />

0.2640<br />

which gives α ≈ 2 h 35 min 3 s, δ ≈ 15.19 ◦ . The exact<br />

direction is α = 2h34min53s,δ = 15.17 ◦ .<br />

Chapter 7<br />

7.1 Assuming the orbits are circular, the greatest<br />

elongation is arcsin(a/1AU). For Mercury this is 23 ◦<br />

and for Venus 46 ◦ . The elongation of a superior planet<br />

can be anything up to 180 ◦ . The sky revolves about 15 ◦<br />

per hour, and thus corresponding times for Mercury and<br />

Venus are 1 h 30 min and 3 h 5 min, respectively. In opposition<br />

Mars is visible the whole night. These values,<br />

however, depend on the actual declinations of the planets.<br />

7.2 a) 8.7 ◦ . b) The Earth must be 90 ◦ from the ascending<br />

node of Venus, which is the situation about<br />

13 days before vernal and autumnal equinoxes, around<br />

March 8 and September 10.<br />

7.3 Psid = 11.9a, a = 5.20 AU, d = 144,000 km.<br />

Obviously the planet is Jupiter.<br />

7.4 a) Hint: If there is a synodic period P there must<br />

be integers p and q such that (n2 − n1)P = 2πp and<br />

(n3 − n1)P = 2πq. Sometimes one can see claims that<br />

the configuration of the whole planetary system will recur<br />

after a certain period. Such claims are obviously<br />

nonsense. b) 7.06 d.<br />

7.5 a) If the radii of the orbits are a1 and a2, the<br />

angular velocity of the retrograde motion is<br />

dλ<br />

dt =<br />

√<br />

GM<br />

√<br />

a1a2( √ a1 + √ a2) .<br />

b) In six days Pluto moves about 0.128 ◦ corresponding<br />

to 4 mm. For a main belt asteroid the displacement is<br />

almost 4 cm.<br />

7.6 If the orbital velocity of the planet is v the<br />

deviation in radians is<br />

α = v<br />

<br />

1 GM⊙<br />

= .<br />

c c a<br />

This is greatest for Mercury, α = 0.00016 rad = 33 ′′ .<br />

This planetary aberration must be taken into account<br />

when computing accurate ephemerides. The deviation<br />

is largest when the planet is in conjunction or opposition<br />

and moves almost perpendicularly to the line of<br />

sight.<br />

7.7 p = 0.11, q = 2, and A = 0.2. In reality the<br />

Moon reflects most of the light directly backwards (opposition<br />

effect), and thus q and A are much smaller.<br />

7.8 ∆m = 0.9. The surface brightness remains constant.<br />

7.9 The absolute magnitude is V(1, 0) = 23.<br />

a) m = 18.7. b) m = 14.2. At least a 15 cm telescope is<br />

needed to detect the asteroid even one day before the<br />

collision.

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