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Implementing IIR/FIR Filters

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φΩ ( ) tan 1 –<br />

d<br />

k<br />

Ω/Ω<br />

c<br />

( Ω/Ω<br />

c<br />

) 2 N/2<br />

= ∑ -----------------------------k<br />

= 1<br />

– 1<br />

Eqn. 5-12<br />

Eqn. 5-11, and Eqn. 5-12 describe the response<br />

characteristics of an N th -order lowpass Butterworth<br />

filter in the continuous frequency analog domain.Since<br />

the quantity of interest is usually 20 log<br />

G(Ω), Eqn. 5-11 can be transformed into a sum<br />

(over the second-order sections) of 20 log (G k ),<br />

where G k is the gain of the k th section. Similarly, the<br />

total phase is just the sum of the phase contribution<br />

by each section from Eqn. 5-12.<br />

The bilinear transformation is used to convert the<br />

continuous frequency domain transfer function into<br />

the digital domain representation, where θ, the normalized<br />

digital domain frequency equal to 2πf/f s ,<br />

can be thought of as the ratio of frequency to sampling<br />

frequency scaled by 2π. Substituting s from<br />

Eqn. 2-13 and Ω c from Eqn. 2-14 into the k th section<br />

of Eqn. 5-7 yields the digital domain form of the Butterworth<br />

lowpass filter (for the k th second-order<br />

section):<br />

H<br />

k<br />

( z)<br />

α<br />

k<br />

1 2z 1 –<br />

z 2 –<br />

( + + )<br />

1<br />

-- γ<br />

2 k<br />

z 1 –<br />

β<br />

k<br />

z 2 –<br />

=<br />

-------------------------------------------------<br />

– +<br />

Eqn. 5-13<br />

MOTOROLA 5-5

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