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An analytic Green's function for a lined circular duct containing ...

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3. Solution<br />

3.1. The hollow <strong>duct</strong><br />

We represent the delta-<strong>function</strong> by a generalised Fourier series in W and Fourier integral in x<br />

Z 1<br />

dðr r0Þ 1<br />

dðx x0Þ ¼ e<br />

r0 2p 1<br />

ikðx x0Þ 1 X<br />

dk<br />

2p<br />

1<br />

m¼ 1<br />

where 0or0o1, and write accordingly<br />

Gðx; r; W; x0; r0; W0Þ ¼ X1<br />

e<br />

m¼ 1<br />

imðW W0Þ<br />

Gmðr; xÞ ¼ X1<br />

m¼ 1<br />

Substitution of Eqs. (6) and (7) in Eq. (2) yields <strong>for</strong> ^ Gm<br />

with<br />

This has solution<br />

q 2 Gm<br />

^ 1 q<br />

þ<br />

qr2 r<br />

^ Gm<br />

qr<br />

a 2 ¼ O 2<br />

þ a2 m2<br />

r 2<br />

e<br />

^Gm ¼<br />

Z 1<br />

imðW W0Þ<br />

1<br />

e imðW W0Þ . (6)<br />

^Gmðr; kÞe ikðx x0Þ dk. (7)<br />

dðr r0Þ<br />

4p2 , (8)<br />

r0<br />

k 2 ; O ¼ o kM. (9)<br />

^Gmðr; kÞ ¼AðkÞJmðarÞþ 1<br />

8p Hðr r0ÞðJmðar0ÞY mðarÞ Y mðar0ÞJmðarÞÞ, (10)<br />

where Jm and Y m denote the m-th order ordinary Bessel <strong>function</strong>s [19] of the first and second kind, Hðr<br />

denotes the Heaviside step<strong>function</strong>. Use is made of the Wronskian<br />

r0Þ<br />

JmðxÞY 0 mðxÞ Y mðxÞJ 0 2<br />

mðxÞ ¼ .<br />

px<br />

(11)<br />

A prime denotes a derivative to the argument, x. AðkÞ is to be determined from the boundary conditions at<br />

r ¼ 1, which is (assuming uni<strong>for</strong>m convergence) per mode<br />

iO 2 Gm<br />

^ þ oZ1 ^ G 0<br />

m ¼ 0<br />

A prime denotes a derivative to r. This yields<br />

at r ¼ 1. (12)<br />

and thus<br />

where<br />

" #<br />

, (13)<br />

A ¼ 1<br />

8p Y mðar0Þ<br />

ARTICLE IN PRESS<br />

S.W. Rienstra, B.J. Tester / Journal of Sound and Vibration 317 (2008) 994–1016 997<br />

iO 2 Y mðaÞþoaZ1Y 0 mðaÞ iO 2 JmðaÞþoaZ1J 0 Jmðar0Þ<br />

mðaÞ ^Gmðr; kÞ ¼JmðaroÞ iO2F mðr4; aÞþoZ1Hmðr4; aÞ<br />

, (14)<br />

8pEmðkÞ<br />

EmðkÞ ¼iO 2 JmðaÞþoaZ1J 0 mðaÞ, (15a)<br />

F mðr; aÞ ¼JmðaÞY mðarÞ Y mðaÞJmðarÞ, (15b)<br />

Hmðr; aÞ ¼aJ 0 m ðaÞY mðarÞ aY 0 m ðaÞJmðarÞ, (15c)<br />

r4 ¼ maxðr; r0Þ, (15d)<br />

ro ¼ minðr; r0Þ. (15e)

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