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LM391 Audio Power Driver

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Application Hints (Continued)<br />

A 40W8X 60W4X AMPLIFIER<br />

Given<br />

<strong>Power</strong> Output<br />

40W8X<br />

60W4X<br />

1V Max<br />

100k<br />

20 Hz–20 kHz g 025 dB<br />

Input Sensitivity<br />

Input Impedance<br />

Bandwidth<br />

Equations (1) and (2) give<br />

40W8X V OPeak e 253V I OPeak e 316A<br />

60W4X V OPeak e 219V I OPeak e 548A<br />

Therefore the supply required is<br />

g303V 316A reducing to <br />

g269V 548A<br />

With 15% regulation and high line we get g383V using<br />

equation (3)<br />

The minimum gain from equation (4) is<br />

A V<br />

t 18<br />

We select a gain of 20 resulting sensitivity is 900 mV<br />

The input impedance and bandwidth are the same as the 20<br />

watt amplifier so the components are the same<br />

R f1 e 51k R IN e 100k C C e 5pF<br />

R f2 e100k C f e 10 mF<br />

The maximum supplies dictate using 80V devices The<br />

2N5882 2N5880 pair are 80V 160W transistors with a minimum<br />

beta of 40 at 2A and 20 at 6A This corresponds to a<br />

minimum beta of 225 at 55A (I Opeak ) The MJE712<br />

MJE722 driver pair are 80V transistors with a minimum beta<br />

of 50 at 250 mA This output combination guarantees I Opeak<br />

with 5 mA from the <strong>LM391</strong><br />

Output transistor heat sink requirements are found using<br />

equations (7) (9) and (10)<br />

P D e 04 (60) e 24W<br />

(7)<br />

200 b 55<br />

i JA<br />

s e 60CW for T AMAX e 55C (9)<br />

24<br />

i SA<br />

s 60 b 11 b 10 e 39CW (10)<br />

For both output transistors on one heat sink the thermal<br />

resistance should be 19CW<br />

Now using equation (8) we find the power dissipation in the<br />

driver<br />

P DRIVER e 24 e 12W (8)<br />

20<br />

150 b 55<br />

i JA<br />

s e 79CW (9)<br />

12<br />

Since a heat sink is required on the driver we should investigate<br />

the output stage thermal stability at the same time to<br />

optimize the design If we find a value of R E that is good for<br />

the protection circuitry we can then use equation (5) to find<br />

the heat sink required for the drivers<br />

The SOA characteristics of the 2N5882 2N5880 transistors<br />

are shown in the following curve along with a desired protection<br />

line<br />

SOA 2N5882 2N5880<br />

TLH7146–10<br />

The desired data points are<br />

V M e 80V V B e 47V I L e 3A I L e 11A<br />

Since the break voltage is not equal to the supply we will<br />

use two resistors to replace R 3 and move V B <br />

Circuit Used<br />

Thevenin Equivalent<br />

TLH7146–11<br />

Where R TH e R A 3 ll R B 3<br />

V TH e V b R<br />

<br />

A 3<br />

R A 3 3( a RB<br />

TLH7146–12<br />

10

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