Ferromagnetic (Ga,Mn)As Layers and ... - OPUS Würzburg
Ferromagnetic (Ga,Mn)As Layers and ... - OPUS Würzburg
Ferromagnetic (Ga,Mn)As Layers and ... - OPUS Würzburg
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
58 4. Finite Element Simulations of Strain Relaxation<br />
1 .0 x 1 0 -3<br />
8 .0 x 1 0 -4<br />
6 .0 x 1 0 -4<br />
4 .0 x 1 0 -4<br />
S tra in<br />
2 .0 x 1 0 -4<br />
0 .0<br />
-2 .0 x 1 0 -4<br />
-4 .0 x 1 0 -4<br />
e (1 1 0 )<br />
e z<br />
e x y<br />
e x = e y<br />
e x (1 0 0 s trip e )<br />
e z (1 0 0 s trip e )<br />
-6 .0 x 1 0 -4<br />
-8 .0 x 1 0 -4<br />
-1 .0 x 1 0 -3<br />
2 4 6 8 1 0<br />
R e la tiv e W id th<br />
Figure 4.8: Simulation of the average strain in a (<strong>Ga</strong>,<strong>Mn</strong>)<strong>As</strong> stripe aligned along the [ 110 ]<br />
crystal direction. The solid lines represent the strain in the cubic directions (blue: e x = e y ,<br />
red: e z ), the shear strain (green: e xy ), <strong>and</strong> the calculated relaxation perpendicular to the<br />
stripe axis (black: e [110] ). The dotted lines are the simulation results for an identical stripe<br />
aligned along [100], taken from Fig. 4.4.<br />
By comparing Eqn. (4.19) <strong>and</strong> Eqn. (4.20), we can now identify:<br />
e [110]<br />
= 1 2 (e x − 2e xy + e y ) (4.21)<br />
e [110] = 1 2 (e x + 2e xy + e y ) (4.22)<br />
For the given material parameters of the stipe, the strain in [1¯10] is equal to<br />
−1.5 · 10 −3 , as no strain relaxation takes place in this direction. The strain e [110]<br />
can be directly compared to e x for a stripe along [100] to determine the difference in<br />
perpendicular relaxation for both geometries. We note that in the rotated matrix E ′ ,<br />
the shear strain vanishes, as we would expect for a stripe aligned with the coordinate<br />
axes.<br />
The strain simulation shown in Fig. 4.8 was compiled by varying the relative width<br />
of a (<strong>Ga</strong>,<strong>Mn</strong>)<strong>As</strong> stripe with identical parameters as discussed in Section 4.3.1.<br />
By comparing the relaxation perpendicular to the stripe, e [110] , with the the corresponding<br />
e x (dotted blue line) of the nonrotated stripe, we can immediately see,<br />
that we achieve a lesser degree of relaxation in this geometry for otherwise identical<br />
structures. This fact is also evident in the larger value of e z in the rotated stripe. The