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Self-Consistent Field Theory and Its Applications by M. W. Matsen

Self-Consistent Field Theory and Its Applications by M. W. Matsen

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20 1 <strong>Self</strong>-consistent field theory <strong>and</strong> its applications<br />

where<br />

c † i = 1 V<br />

∫<br />

dr f i (r)q † (r, 1) (1.69)<br />

In practice, it is impossible to complete the infinite sums in Eqs. (1.66) <strong>and</strong> (1.68), but the<br />

eigenvalues are appropriately ordered such that the terms become less <strong>and</strong> less important.<br />

Therefore, the sums can be truncated at some point, i = M, where the number of terms<br />

retained, M +1, is guided <strong>by</strong> the desired level of accuracy.<br />

1.5.2 Ground-State Dominance<br />

The previous expansion for q(r,s) in Eq. (1.66) becomes increasingly dominated <strong>by</strong> the first<br />

term involving the ground-state eigenvalue, λ 0 , the further s is from the end of the chain. For<br />

a high-molecular-weight polymer, the approximations,<br />

<strong>and</strong><br />

q(r,s) ≈ c 0 exp(−λ 0 s)f 0 (r) (1.70)<br />

q † (r,s) ≈ c † 0 exp(−λ 0(1 − s))f 0 (r) (1.71)<br />

become accurate over the vast majority of the chain. In this case, it follows that the partition<br />

function of the entire chain is<br />

Q[w] ≈Vc 0 c † 0 exp(−λ 0) (1.72)<br />

<strong>and</strong> that the segment concentration is<br />

φ α (r) ≈<br />

N<br />

ρ 0 V f 0 2 (r) (1.73)<br />

These simplifications permit us to derive an analytical L<strong>and</strong>au-Ginzburg free energy expression<br />

for the entropic energy, f e , of the polymer as a function of its concentration profile,<br />

φ α (r). Our derivation will assume that concentration gradient,<br />

∇φ α (r) = 2N<br />

ρ 0 V f 0(r)∇f 0 (r) (1.74)<br />

is zero at the extremities (i.e., boundaries) of our system, V.<br />

The first step of the derivation is to multiply Eq. (1.59) for i =0<strong>by</strong> f 0 (r) <strong>and</strong> integrate<br />

over V, producing the result,<br />

ρ 0<br />

N<br />

∫<br />

dr w(r)φ α (r) = a2 N<br />

6V<br />

∫<br />

dr f 0 (r)∇ 2 f 0 (r)+λ 0 (1.75)<br />

Next, this expression for the field energy along with Eq. (1.72) for Q[w] are inserted into Eq.<br />

(1.34) giving the expression,<br />

∫<br />

f e<br />

k B T = − a2 N<br />

dr f 0 (r)∇ 2 f 0 (r) − ln(c 0 c † 0<br />

6V<br />

) (1.76)

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