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Frost Protection - UTL Repository

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ACTIVE PROTECTION METHODS<br />

temperature. When the wind speed is higher, there is more evaporation, higher<br />

sensible heat losses from the plant surfaces and more water must be frozen to<br />

compensate for these losses. When the unprotected minimum temperature is<br />

lower, then more energy from the freezing process is needed to make up for the<br />

sensible heat deficit. Sprinkler rotation rates are important because the<br />

temperature of wet plant parts rises when the water freezes, but it falls as water<br />

vaporizes and radiative losses continue between pulses of water striking the<br />

plants (Figure 7.10).<br />

Frequent wetting of the crop is needed to reduce the time interval when the<br />

plant temperature falls below 0 °C (Figure 7.10). Generally, the rotation rate<br />

should not be longer than 60 seconds and 30 seconds is better. For example, the<br />

widely used sprinkler application rate recommendations for grapevines for wind<br />

speeds of 0.0 to 0.5 m s -1 (Table 7.7) and wind speeds of 0.9 to 1.4 m s -1 (Table 7.8)<br />

depend on the sprinkler rotation rate and minimum temperature as well as the<br />

wind speed. Gerber and Martsolf (1979) presented a theoretical model for<br />

overhead sprinkler application rate for protection of a 20 mm diameter tree leaf.<br />

Using that model a simple empirical equation giving nearly the same sprinkler<br />

application rate (R A ) is given by:<br />

R A = ( 0.0538 u 2 − 0.5404 u − 0.4732 ) T l mm h -1 Eq. 7.7<br />

where u (m s -1 ) is the wind speed and T l (°C) is the temperature of a dry<br />

unprotected leaf.<br />

Using the approach outlined by Campbell and Norman (1998), the difference<br />

between air and leaf temperature of a 0.02 m diameter leaf on a typical frost<br />

night, with high stomatal resistance, can be estimated as:<br />

T a − T l = 1.4458 u -0.4568 °C Eq. 7.8<br />

for 0.1 ≤ u ≤ 5ms -1 . Combining the two equations, a simple equation for the<br />

sprinkler application rate in terms of wind speed (u) in m s -1 and air temperature<br />

(T a ) in °C is given by:<br />

R A = ( T a − 1.4458 u -0.4568 ) ( 0.0538 u 2 − 0.5404 u - 0.4732 ) mm h -1 Eq. 7.9<br />

171

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