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Download full text - ELSA - Europa

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Stress Update<br />

• To solve the equilibrium equation for the new accelerations:<br />

u M ( f B σ dV )<br />

= −∑ ∫<br />

n+ 1 − 1 ext( n+ 1) T e( n+<br />

1)<br />

e e( n+<br />

1)<br />

V<br />

one needs the new stress en ( 1)<br />

.<br />

σ +<br />

• In general one may formally write:<br />

n 1 n<br />

σ σ σ<br />

+ = +∆<br />

n<br />

∆ σ = H( σ , ∆ε, p, ε, …) (Rate form)<br />

H Constitutive law<br />

∆σ stress increment over the step<br />

∆ε strain increment over the step<br />

p hardening parameters (e.g. plasticity)<br />

ε strain rate (e.g. viscous behaviour)<br />

• Note that the total deformation does not appear anywhere<br />

and is not used in the process.<br />

23<br />

ε<br />

Elasto-plastic material<br />

As an example of non-linear material behaviour consider the<br />

important case of metal plasticity:<br />

• Rate-independent deviatoric plasticity model with Von<br />

Mises yield criterion:<br />

• “Trial” stress (elastic):<br />

trial<br />

σn+ 1<br />

= σn + C ⋅∆ε<br />

Radial return<br />

method<br />

(Wilkins)<br />

σ n<br />

σ 3<br />

σ<br />

n + 1<br />

σ σ<br />

1<br />

2<br />

• If trial stress lies outside yield surface, perform radial<br />

return onto (current) yield surface. No iterations!<br />

trial<br />

σ<br />

n + 1<br />

How does one compute ∆ε from displacement increments (or velocities) in the presence of<br />

geometrical non-linearities (large strains and large motions, in particular large rotations?)<br />

24<br />

12

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