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log 1 dtml REZO GAM0 0.5 FLMP EPS1 5.0E-4 EPS2 1.0E-4 CALCUL TINI 0 TEND 50.E-3 *================================================================= SUIT Post-treatment (time curves from alice temps file) ECHO * RESU ALIC TEMP GARD PSCR * SORT GRAP * AXTE 1000.0 'Time [ms]' * COUR 1 'dz_n1' DEPL COMP 3 NOEU LECT tpn1 TERM COUR 2 'dx_n2' DEPL COMP 1 NOEU LECT tpn2 TERM COUR 3 'dx_n3' DEPL COMP 1 NOEU LECT tpn3 TERM * trac 1 2 3 axes 1.0 'DISPL. [M]' trac 2 3 axes 1.0 'DISPL. [M]' * QUAL DEPL COMP 3 LECT tpn1 TERM REFE 1.23254E+0 TOLE 5.E-2 DEPL COMP 1 LECT tpn2 TERM REFE -1.24733E-2 TOLE 1.E-1 DEPL COMP 1 LECT tpn3 TERM REFE -4.01831E-2 TOLE 5.E-2 *================================================================= FIN 10
Some results: final pressure distribution: Final water distribution: 11
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European Laboratory for Structural
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Proceedings of a Course on: Numeric
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Programme of the Course 1. Introduc
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Credits & Acknowledgments • Struc
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Introductory Example (4) 7 Applicat
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x Computational Framework • Gover
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n+ 1 n ∆t n n+ 1 u = u + ( u + u
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Scheme start-up and marching (2)
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Stress Update • To solve the equi
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Geometric non-linearities (3) Set u
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Essential Boundary Conditions Essen
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Exercise 0 - Ideal ballistics • M
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Exercise 0 - Ideal ballistics (5)
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Exercise 1 - Suspended mass (3) •
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Exercise 1 - Suspended mass (7) •
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Exercise 2 - Wave propagation (4)
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Exercise 3 - Impact on Cooling Towe
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TITLE: PMAT04: motion of projectile
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sinon; tra2 = tra2 et ele; finsi; f
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Some results: horizontal and vertic
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PMAT01E This test is similar to PMA
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Hence: 11 −8 ES 2× 10 ⋅ 2.5×
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The stress history is: Note that th
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Analytical TEST11 Same as TEST01 bu
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Comparison of natural vs. engineeri
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The total external forces at the tw
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TEST13 Same as TEST01 but uses a 10
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The mass returns at the initial pos
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TEST22 To verify the independence o
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Linear dynamic analysis Consider th
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• The two waves f and g propagate
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Analytical solution For the bar imp
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Note that we have also put the Pois
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BARI08 We study the effect of the t
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ENDPLAY *==========================
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BARI10 Same as BARI09 but compares
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The system is initially at rest, an
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CAST MESH TRID NONL LAGR $ $ Dimens
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Final deformation (with superposed
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Detailed Contents • Modeling the
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Modeling the fluid domain • The f
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Euler equations (3) • For a compr
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Time integration Each time incremen
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Time integration (5) 10. Account fo
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Euler Equations (FV) • They are w
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Mesh rezoning - motivations • Rez
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Giuliani’s automatic rezoning •
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• Analytical solution (self-simil
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Shock tube (6) • Influence of pse
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Exercise 2 - Explosion in air-fille
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Exercise 3 - Bubble expansion in a
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Exercise 4 - External blast on two
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Geometric data: The calculation is
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SHOC01 Eulerian, “average” pseu
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COUR 7 'ro_a' ECRO COMP 2 ELEM LECT
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Analytical Conclusion: the pseudo-v
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SHOC13 Eulerian, very low pseudo-vi
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Analytical General conclusions: •
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The inverse path is not so straight
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The input files (mesh generation by
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Geometric data: The calculation is
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COUR 1 'dx_4' DEPL COMP 1 NOEU LECT
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TANK02 Eulerian solution: the whole
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The final pressure distribution is:
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TUBE06 Lagrangian solution: the who
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And the final velocity distribution
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The computed displacements are: To
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43 30 30 43 44 31 31 44 45 32 32 45
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Geometric data: External blast in a
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abs4 = dall (p4 d 28 p4u) (p4u d 40
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Geometric data: Internal blast in a
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air = air1 ET air2 ET air3 ET air4
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COURBE 8 'P e_p12' ECROU COMP 1 lec
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3D axisymmetric simulation: JWLS3G
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point lect 1 term elem lect 1 term
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Universitat Politècnica de Catalun
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• Motivation Detailed Contents
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FSI Classification FSI for compress
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The 2-D plane case (2) Use geometri
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Classification of FSI algorithms
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The FSA algorithm (4) The case of s
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The FSCR algorithm Combination of F
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Application to Finite Volumes (3) 2
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Exercise 2 - Explosions in simple d
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Exercise/Example 3 - Wave propagati
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Exercise/Example 4 - CONT problem (
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Exercise/Example 5 - Explosion in a
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Exercise/Example 6 : Woodward-Colel
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Geometry: Exercise/Example 8 Steam
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Exercise/Example 9 Explosion in Sec
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Exercise/Example 9 Explosion in Sec
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Boundary Condition Elements: CLxx (
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Exercise/Example 11 - Perforated Pl
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Exercise/Example 12 - Sloshing (3)
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DIME PT3L 23 PT2L 143 FL24 145 ED01
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The final pressure field in the flu
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ALE solution with FSA: it is not po
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Page 222 and 223: and the final velocity field: The s
Page 224 and 225: The final velocities: The final liq
Page 226 and 227: *----------------------------------
Page 228 and 229: TWIS07 We study the phenomenon by a
Page 231 and 232: This is a well-known reactor safety
Page 233 and 234: 1.53330E+00 1.32310E+01 1.15000E+00
Page 235 and 236: 200 199 239 240 200 200 200 240 241
Page 237 and 238: *----------------------------------
Page 239 and 240: The final fluid pressures: CONT02 T
Page 241 and 242: The final fluid velocities: The fin
Page 243 and 244: This example consists in a long 3D
Page 245 and 246: GEOM FL38 flui Q4GS stru TERM COMP
Page 248 and 249: Detail of first diaphragm: Detail o
Page 250 and 251: BOUNDARY CONDITIONS: The step is en
Page 252 and 253: The EUROPLEXUS input file reads: WO
Page 254 and 255: WOCO3D The mesh generation file (K2
Page 256 and 257: * RESU ALIC GARD PSCR * SORT GRAP *
Page 258 and 259: PT3L 16389 PT6L 504 NBLE 16389 NALE
Page 260 and 261: Final pressure distribution: 4
Page 262 and 263: BOUNDARY CONDITIONS: The vessel is
Page 264 and 265: as01=daller c1 c2 c3 c4 plan; * c1=
Page 266 and 267: *trac oeil cach fluidstr; *opti don
Page 268 and 269: cam3=cam31 et cam32; camb=cam1 et c
Page 272 and 273: Final structure deformation: Final
Page 274 and 275: LOADING: The event is initiated by
Page 276 and 277: FLUT RO .242777373 EINT 6.865E5 GAM
Page 278 and 279: Final structure velocities: 6
Page 280 and 281: RESULTS: A paper by Bermudez and Ro
Page 282 and 283: The applied displacement and the co
Page 284 and 285: PROBLEM: A rigid tank with a deform
Page 286: The EUROPLEXUS input file reads: GR
Page 289 and 290: PROBLEM: A rigid tank with rigid or
Page 291 and 292: COMP EPAI 0.005 LECT 101 102 103 10
Page 293 and 294: Numerical Solution (flexible bottom
Page 295 and 296: ! VARI DEPL VITE ECRO ! fich alic t
Page 297 and 298: The final pressures in the rigid an
Page 299 and 300: LOADING: A constant gravity in the
Page 301 and 302: Some results: intermediate and fina
Page 305 and 306: Universitat Politècnica de Catalun
Page 307 and 308: ALE description of structures (2)
Page 309 and 310: Example 1 - Taylor bar impact (3) B
Page 311 and 312: Example 3 - Coining (3) Influence o
Page 313 and 314: • Tentative classification: Non-c
Page 315 and 316: Example 4 - Explosion in a 2D box (
Page 317 and 318: Example 6 - LOCA in the HDR (2) A -
Page 319 and 320: Examples of “Slow” Transient Co
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Examples of Fast Transient Impact
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Components of Contact-Impact Method
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Shortcomings • Slender or distort
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Example - Bar impact • (See Part
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Example 7b - Indentation (2) • 2D
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Example 7b - Indentation (6) • 3D
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Smoothed Particles Hydrodynamics (C
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SPH Formulation (2) • Basic idea:
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SPH impact [Courtesy of Samtech/Son
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PRGL01: Example 8 - SPH impacts (Co
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Spectral Elements • Motivation: l
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Spectral Elements (5) Convergence p
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Example 9 - Closed FE/SE interface
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Example 11 - Cylindrical valley 85
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Performance Optimization • All ex
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Time Step Partitioning (4) • Intr
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Time Step Partitioning (8) • Acti
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Treatment of links in partitioning
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Example 12a - Taylor bar impact rev
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Coupling at the Interfaces • Two
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Coupling at the Interfaces (5) MU T
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Coupling at the Interfaces (9) Time
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Multiple scales in time (3) • Exp
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Multiple scales in space • Furthe
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Multiple scales in frequency • So
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Example: power plant 133 Example: p
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Example: aircraft (3) Thanks to CPU
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Example 14 - Domains in 3D • Thic
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Example 15 - Bar Impact Revisited (
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* mesh=stru et symax et viti et lil
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The displacements are: 4
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c2=p1 d 8 p2; c3=p2 d 20 p3; c4=p3
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The resulting final deformed mesh w
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TERM *-----------------------------
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Geometric data and materials: The b
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BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56
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INFS02 We use a twice finer fluid m
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FREQ 1 GOTR LOOP 60 OFFS FICH AVI C
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Problem description: This example i
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*----------------------------------
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The final velocities: The final for
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*----------------------------------
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The final deformed mesh is: The fin
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pc = 4.5 -1 -1.5; pd = 5.5 -1 -1.5;
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The initial configuration (with par
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TITLE: Indentation problem. PROBLEM
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cp = p0 d 10 p13; elim tol (piece e
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The final velocities: The final dis
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The input file is: INDE - 13 ECHO !
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The final displacement norm: The fi
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elim tol (piece et cp); c_p = piece
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The final deformed shape is: 13
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Numerical Solutions PRGL01 Simplifi
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FOV 2.48819E+01 SCEN GEOM NAVI FREE
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ROMA01 Final plastic streen in the
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SONA01 7
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Final density in the projectile: Fi
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opti echo 0; opti donn 'D:\Users\Fo
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* opti dime 2 elem qua4; p0 = 0 0;
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The final X-displacement in the hyb
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* opti dime 2 elem qua4; opti titr
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VALLPS This calculation assumes a p
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The receiver signal in the coupled
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Problem description: This example r
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CALC TINI 0. TFIN 40.E-3 *=========
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REPETER BCL2 (2); REPETER BCL3 (2);
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*----------------------------------
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The tip displacement in the referen
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LOG 1 DPSD *-----------------------
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TRAC CACH OEIL2 ZONE1; TRAC CACH OE
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The tip displacement in the referen
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$ INIT VITE 2 -227. LECT VITI TERM
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* AXTE 1000.0 'Time [ms]' * COUR 1
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sq41=sq41 coul 'TURQ'; sq42=sq42 co
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The displacements in the case with
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European Commission DG Joint Resear
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