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120 119 138 139 121 120 139 140 122 121 140 141 123 122 141 142 124 123 142 143 125 124 143 144 126 125 144 145 *--------------------------------------------------Geometric Complements COMP GROU 3 'expl' LECT 1 PAS 1 12 TERM 'liq' LECT 13 PAS 1 96 TERM 'stru' LECT 97 PAS 1 114 TERM COUL roug LECT expl TERM turq LECT liq TERM rose LECT stru TERM EPAIS 0.02 LECT stru TERM *------------------------------------------------------------Grid Motion GRIL LAGR LECT 1 PAS 1 14 67 PAS 1 73 PAS 7 101 PAS 1 107 PAS 1 145 TERM ALE TOUS AUTO AUTR *----------------------------------------------------------Material data MATE FLUT RO 1.E3 EINT 0 GAMM 2.E9 PB 0 ITER 1 ALF0 1 BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56 PMIN 0 NUM 9 LECT 13 PAS 1 96 TERM FLUT RO 1.E2 EINT 2.5E5 GAMM 1.4 PB 0 ITER 1 ALF0 1 BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56 PMIN 0 NUM 1 LECT 1 PAS 1 12 TERM VM23 RO 7800. YOUNG 1.6E11 NU 0.333 ELAS 1.05E8 TRAC 2 1.05E8 .656256E-3 1.6105E10 1.00066 LECT stru TERM *----------------------------------------------------Boundary conditions LINK COUP BLOQ 1 LECT 1 14 PAS 13 79 PAS 7 107 TERM BLOQ 2 LECT 1 67 2 15 28 41 54 108 127 TERM BLOQ 3 LECT 108 127 TERM LINK DECO FSS LAGR NCT1 10 LECT 61 67 68 TERM LECT 62 68 69 TERM LECT 63 69 70 TERM LECT 64 70 71 TERM LECT 65 71 72 TERM LECT 66 72 73 TERM LECT 73 73 80 TERM LECT 79 80 87 TERM LECT 85 87 94 TERM LECT 91 94 101 TERM NPOI 11 NCT2 18 LECT 97 108 109 TERM LECT 98 109 110 TERM LECT 99 110 111 TERM LECT 100 111 112 TERM LECT 101 112 113 TERM LECT 102 113 114 TERM LECT 103 114 115 TERM LECT 104 115 116 TERM LECT 105 116 117 TERM LECT 106 117 118 TERM LECT 107 118 119 TERM LECT 108 119 120 TERM LECT 109 120 121 TERM LECT 110 121 122 TERM LECT 111 122 123 TERM LECT 112 123 124 TERM LECT 113 124 125 TERM LECT 114 125 126 TERM NPOI 19 *----------------------------------------------------------------Outputs ECRI COOR DEPL VITE CONT ECRO TFRE 100.E-3 FICH ALIC TEMP FREQ 1 POIN LECT 101 107 TERM ELEM LECT 1 91 TERM *----------------------------------------------------------------Options OPTI NOTE csta 0.5 log 1 rezo gam0 0.5 *--------------------------------------------------Transient calculation CALCUL TINI 0 TEND 500.E-3 *==============================================================ANIMATION PLAY CAME 1 EYE 0.00000E+00 0.00000E+00 1.19817E+02 ! Q 1.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 VIEW 0.00000E+00 0.00000E+00 -1.00000E+00 RIGH 1.00000E+00 0.00000E+00 0.00000E+00 UP 0.00000E+00 1.00000E+00 0.00000E+00 FOV 3.00000E+01 8
scen geom navi free !vect scco scal user prog 0.e0 pas 2.e0 2.6e1 term !<strong>text</strong> vsca colo pape freq 0 tfre 2.e-3 sler cam1 1 nfra 1 trac offs fich avi nocl nfto 251 fps 10 kfre 10 comp -1 symx symy rend gotr loop 249 offs fich avi cont nocl symx symy rend go trac offs fich avi cont symx symy rend ENDPLAY *=========================================================POST-TREATMENT SUIT Post-treatment ECHO RESU ALIC TEMP GARD PSCR SORT GRAP AXTE 1000.0 'Time [ms]' *------------------------------------------------------Curve definitions COUR 1 'dy_2' DEPL COMP 2 NOEU LECT 101 TERM COUR 2 'dy_3' DEPL COMP 2 NOEU LECT 107 TERM COUR 3 'pr_1' ECRO COMP 1 ELEM LECT 1 TERM COUR 4 'pr_2' ECRO COMP 1 ELEM LECT 91 TERM *------------------------------------------------------------------Plots trac 1 2 axes 1.0 'DISPL. [M]' yzer trac 3 4 axes 1.0 'PRESS. [PA]' *--------------------------------------------------Results qualification QUAL DEPL COMP 2 LECT 101 TERM REFE 5.43306E+00 TOLE 1.E-2 DEPL COMP 2 LECT 107 TERM REFE 6.07702E+00 TOLE 1.E-2 ECRO COMP 1 LECT 1 TERM REFE 3.80273E+04 TOLE 1.E-2 ECRO COMP 1 LECT 91 TERM REFE 0.00000E+00 TOLE 1.E-2 *======================================================================= FIN The final deformed mesh: 9
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European Laboratory for Structural
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Proceedings of a Course on: Numeric
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Programme of the Course 1. Introduc
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Credits & Acknowledgments • Struc
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Introductory Example (4) 7 Applicat
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x Computational Framework • Gover
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n+ 1 n ∆t n n+ 1 u = u + ( u + u
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Scheme start-up and marching (2)
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Stress Update • To solve the equi
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Geometric non-linearities (3) Set u
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Essential Boundary Conditions Essen
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Exercise 0 - Ideal ballistics • M
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Exercise 0 - Ideal ballistics (5)
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Exercise 1 - Suspended mass (3) •
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Exercise 1 - Suspended mass (7) •
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Exercise 2 - Wave propagation (4)
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Exercise 3 - Impact on Cooling Towe
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TITLE: PMAT04: motion of projectile
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sinon; tra2 = tra2 et ele; finsi; f
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Some results: horizontal and vertic
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PMAT01E This test is similar to PMA
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Hence: 11 −8 ES 2× 10 ⋅ 2.5×
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The stress history is: Note that th
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Analytical TEST11 Same as TEST01 bu
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Comparison of natural vs. engineeri
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The total external forces at the tw
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TEST13 Same as TEST01 but uses a 10
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The mass returns at the initial pos
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TEST22 To verify the independence o
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Linear dynamic analysis Consider th
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• The two waves f and g propagate
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Analytical solution For the bar imp
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Note that we have also put the Pois
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BARI08 We study the effect of the t
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ENDPLAY *==========================
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BARI10 Same as BARI09 but compares
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The system is initially at rest, an
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CAST MESH TRID NONL LAGR $ $ Dimens
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Final deformation (with superposed
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Detailed Contents • Modeling the
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Modeling the fluid domain • The f
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Euler equations (3) • For a compr
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Time integration Each time incremen
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Time integration (5) 10. Account fo
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Euler Equations (FV) • They are w
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Mesh rezoning - motivations • Rez
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Giuliani’s automatic rezoning •
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• Analytical solution (self-simil
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Shock tube (6) • Influence of pse
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Exercise 2 - Explosion in air-fille
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Exercise 3 - Bubble expansion in a
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Exercise 4 - External blast on two
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Geometric data: The calculation is
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SHOC01 Eulerian, “average” pseu
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COUR 7 'ro_a' ECRO COMP 2 ELEM LECT
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Analytical Conclusion: the pseudo-v
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SHOC13 Eulerian, very low pseudo-vi
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Analytical General conclusions: •
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The inverse path is not so straight
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The input files (mesh generation by
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Geometric data: The calculation is
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COUR 1 'dx_4' DEPL COMP 1 NOEU LECT
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TANK02 Eulerian solution: the whole
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The final pressure distribution is:
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TUBE06 Lagrangian solution: the who
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And the final velocity distribution
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The computed displacements are: To
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43 30 30 43 44 31 31 44 45 32 32 45
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Geometric data: External blast in a
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abs4 = dall (p4 d 28 p4u) (p4u d 40
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Geometric data: Internal blast in a
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air = air1 ET air2 ET air3 ET air4
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COURBE 8 'P e_p12' ECROU COMP 1 lec
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3D axisymmetric simulation: JWLS3G
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point lect 1 term elem lect 1 term
Page 169 and 170: Universitat Politècnica de Catalun
Page 171 and 172: • Motivation Detailed Contents
Page 173 and 174: FSI Classification FSI for compress
Page 175 and 176: The 2-D plane case (2) Use geometri
Page 177 and 178: Classification of FSI algorithms
Page 179 and 180: The FSA algorithm (4) The case of s
Page 181 and 182: The FSCR algorithm Combination of F
Page 183 and 184: Application to Finite Volumes (3) 2
Page 185 and 186: Exercise 2 - Explosions in simple d
Page 187 and 188: Exercise/Example 3 - Wave propagati
Page 189 and 190: Exercise/Example 4 - CONT problem (
Page 191 and 192: Exercise/Example 5 - Explosion in a
Page 193 and 194: Exercise/Example 6 : Woodward-Colel
Page 195 and 196: Geometry: Exercise/Example 8 Steam
Page 197 and 198: Exercise/Example 9 Explosion in Sec
Page 199 and 200: Exercise/Example 9 Explosion in Sec
Page 201 and 202: Boundary Condition Elements: CLxx (
Page 203 and 204: Exercise/Example 11 - Perforated Pl
Page 205 and 206: Exercise/Example 12 - Sloshing (3)
Page 207 and 208: Exercise/Example 12 - Sloshing (7)
Page 209: Exercise/Example 12 - Sloshing (11)
Page 214 and 215: DIME PT3L 23 PT2L 143 FL24 145 ED01
Page 216 and 217: The final pressure field in the flu
Page 218 and 219: ALE solution with FSA: it is not po
Page 222 and 223: and the final velocity field: The s
Page 224 and 225: The final velocities: The final liq
Page 226 and 227: *----------------------------------
Page 228 and 229: TWIS07 We study the phenomenon by a
Page 231 and 232: This is a well-known reactor safety
Page 233 and 234: 1.53330E+00 1.32310E+01 1.15000E+00
Page 235 and 236: 200 199 239 240 200 200 200 240 241
Page 237 and 238: *----------------------------------
Page 239 and 240: The final fluid pressures: CONT02 T
Page 241 and 242: The final fluid velocities: The fin
Page 243 and 244: This example consists in a long 3D
Page 245 and 246: GEOM FL38 flui Q4GS stru TERM COMP
Page 248 and 249: Detail of first diaphragm: Detail o
Page 250 and 251: BOUNDARY CONDITIONS: The step is en
Page 252 and 253: The EUROPLEXUS input file reads: WO
Page 254 and 255: WOCO3D The mesh generation file (K2
Page 256 and 257: * RESU ALIC GARD PSCR * SORT GRAP *
Page 258 and 259: PT3L 16389 PT6L 504 NBLE 16389 NALE
Page 260 and 261: Final pressure distribution: 4
Page 262 and 263: BOUNDARY CONDITIONS: The vessel is
Page 264 and 265: as01=daller c1 c2 c3 c4 plan; * c1=
Page 266 and 267: *trac oeil cach fluidstr; *opti don
Page 268 and 269: cam3=cam31 et cam32; camb=cam1 et c
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log 1 dtml REZO GAM0 0.5 FLMP EPS1
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Final structure deformation: Final
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LOADING: The event is initiated by
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FLUT RO .242777373 EINT 6.865E5 GAM
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Final structure velocities: 6
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RESULTS: A paper by Bermudez and Ro
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The applied displacement and the co
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PROBLEM: A rigid tank with a deform
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The EUROPLEXUS input file reads: GR
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PROBLEM: A rigid tank with rigid or
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COMP EPAI 0.005 LECT 101 102 103 10
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Numerical Solution (flexible bottom
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! VARI DEPL VITE ECRO ! fich alic t
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The final pressures in the rigid an
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LOADING: A constant gravity in the
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Some results: intermediate and fina
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Universitat Politècnica de Catalun
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ALE description of structures (2)
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Example 1 - Taylor bar impact (3) B
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Example 3 - Coining (3) Influence o
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• Tentative classification: Non-c
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Example 4 - Explosion in a 2D box (
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Example 6 - LOCA in the HDR (2) A -
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Examples of “Slow” Transient Co
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Examples of Fast Transient Impact
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Components of Contact-Impact Method
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Shortcomings • Slender or distort
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Example - Bar impact • (See Part
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Example 7b - Indentation (2) • 2D
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Example 7b - Indentation (6) • 3D
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Smoothed Particles Hydrodynamics (C
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SPH Formulation (2) • Basic idea:
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SPH impact [Courtesy of Samtech/Son
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PRGL01: Example 8 - SPH impacts (Co
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Spectral Elements • Motivation: l
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Spectral Elements (5) Convergence p
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Example 9 - Closed FE/SE interface
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Example 11 - Cylindrical valley 85
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Performance Optimization • All ex
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Time Step Partitioning (4) • Intr
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Time Step Partitioning (8) • Acti
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Treatment of links in partitioning
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Example 12a - Taylor bar impact rev
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Coupling at the Interfaces • Two
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Coupling at the Interfaces (5) MU T
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Coupling at the Interfaces (9) Time
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Multiple scales in time (3) • Exp
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Multiple scales in space • Furthe
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Multiple scales in frequency • So
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Example: power plant 133 Example: p
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Example: aircraft (3) Thanks to CPU
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Example 14 - Domains in 3D • Thic
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Example 15 - Bar Impact Revisited (
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* mesh=stru et symax et viti et lil
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The displacements are: 4
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c2=p1 d 8 p2; c3=p2 d 20 p3; c4=p3
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The resulting final deformed mesh w
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TERM *-----------------------------
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Geometric data and materials: The b
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BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56
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INFS02 We use a twice finer fluid m
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FREQ 1 GOTR LOOP 60 OFFS FICH AVI C
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Problem description: This example i
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*----------------------------------
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The final velocities: The final for
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*----------------------------------
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The final deformed mesh is: The fin
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pc = 4.5 -1 -1.5; pd = 5.5 -1 -1.5;
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The initial configuration (with par
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TITLE: Indentation problem. PROBLEM
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cp = p0 d 10 p13; elim tol (piece e
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The final velocities: The final dis
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The input file is: INDE - 13 ECHO !
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The final displacement norm: The fi
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elim tol (piece et cp); c_p = piece
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The final deformed shape is: 13
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Numerical Solutions PRGL01 Simplifi
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FOV 2.48819E+01 SCEN GEOM NAVI FREE
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ROMA01 Final plastic streen in the
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SONA01 7
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Final density in the projectile: Fi
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opti echo 0; opti donn 'D:\Users\Fo
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* opti dime 2 elem qua4; p0 = 0 0;
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The final X-displacement in the hyb
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* opti dime 2 elem qua4; opti titr
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VALLPS This calculation assumes a p
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The receiver signal in the coupled
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Problem description: This example r
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CALC TINI 0. TFIN 40.E-3 *=========
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REPETER BCL2 (2); REPETER BCL3 (2);
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*----------------------------------
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The tip displacement in the referen
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LOG 1 DPSD *-----------------------
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TRAC CACH OEIL2 ZONE1; TRAC CACH OE
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The tip displacement in the referen
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$ INIT VITE 2 -227. LECT VITI TERM
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* AXTE 1000.0 'Time [ms]' * COUR 1
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sq41=sq41 coul 'TURQ'; sq42=sq42 co
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The displacements in the case with
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European Commission DG Joint Resear
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