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FSA LECT 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 TERM $ FONC 1 TABL 642 0 0 . . . (skip for brevity) 12.8304 -0.0006 $ $ Carichi $ CHAR 1 FACT 2 FORCE 2 264 LECT 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 TERM TABL 3 0.0 1.0 1.0 0.0 20.0 0.0 $ CONST GRAV 0.0 -9.81 $ ECRI DEPL POINT LECT 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 TERM TFRE 0.25 ! FICH FORM AVS TFRE 0.025 ! VARI DEPL VITE ECRO ! fich alic temp TFRE 5.E-5 ! poin lect 11 106 126 term ! elem lect 1 term FICH ALIC TFRE 10.E-3 OPTI NOTEST log 100 CALCUL TINI 0 TEND 6.0 NMAX 50000000 *================================================================= SUIT Post-treatment ECHO * !RESU ALIC TEMP GARD PSCR RESU ALIC GARD PSCR * FONC 1 TABL 642 0 0 1 0 1.018485 0.098016 . . . (skip for brevity) 12.8304 -0.0006 * SORT GRAP * AXTE 1.0 'Time [s]' * COUR 1 'dx_11' DEPL COMP 1 NOEU LECT 11 TERM COUR 2 'dy_11' DEPL COMP 2 NOEU LECT 11 TERM COUR 3 'dx_106' DEPL COMP 1 NOEU LECT 106 TERM COUR 4 'dy_106' DEPL COMP 2 NOEU LECT 106 TERM COUR 5 'dx_126' DEPL COMP 1 NOEU LECT 126 TERM COUR 6 'dy_126' DEPL COMP 2 NOEU LECT 126 TERM DCOU 7 'fonc_1' FONC 1 * trac 1 2 3 4 5 6 axes 1.0 'DISPL. [M]' trac 7 axes 1.0 'FUNCTION 1' * QUAL DEPL COMP 1 LECT 11 TERM REFE 0.00000E+0 TOLE 5.E-3 DEPL COMP 2 LECT 11 TERM REFE -2.97067E-4 TOLE 5.E-3 DEPL COMP 1 LECT 106 TERM REFE 0.00000E+0 TOLE 5.E-3 DEPL COMP 2 LECT 106 TERM REFE -1.81780E-4 TOLE 5.E-3 DEPL COMP 1 LECT 126 TERM REFE 0.00000E+0 TOLE 5.E-3 DEPL COMP 2 LECT 126 TERM REFE -1.81780E-4 TOLE 5.E-3 *================================================================= FIN 14
Numerical Solution (flexible bottom) TANK6F The EUROPLEXUS input file reads: TANK - 5mm Uniform Horizontal $ $ FONDO FLESSIBILE, TABELLA DETTAGLIATA, $ AMPIEZZA DI OSCILLAZIONE 9.3mm $ ECHO !CONV win $ 2D Plane Strain + NonLinear + ALE DPLA NONL NAVI ALE $ DIME PT2L 256 PT3L 4 CAR1 200 COQU 30 TRIA 2 ED01 2 $obsolete: MATE 20 NALE 100 NBLE 500 FSA 100 IFSA 500 SLPN 200 SLPC 100 NDVC 400 TABL 200 200 MTPO 200 BLOQ 100 DDLI 100 FCOE 100 FNOM 10 FTAB 800 FORC 24 ZONE 10 TERM $ GEOM LIBR POIN 157 CAR1 100 COQU 20 TRIA 2 ED01 2 TERM $ $ 1 0.00 0.00 . . . (skip for brevity) $ COMP EPAI 0.005 LECT 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 TERM 1.0 LECT 123 124 TERM $ GRIL LAGR LECT 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 1 21 106 126 148 PAS 1 157 TERM $ ALE LECT 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 15
Page 1 and 2:
European Laboratory for Structural
Page 3 and 4:
Proceedings of a Course on: Numeric
Page 5:
Programme of the Course 1. Introduc
Page 10 and 11:
Credits & Acknowledgments • Struc
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Introductory Example (4) 7 Applicat
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x Computational Framework • Gover
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n+ 1 n ∆t n n+ 1 u = u + ( u + u
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Scheme start-up and marching (2)
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Stress Update • To solve the equi
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Geometric non-linearities (3) Set u
Page 24 and 25:
Essential Boundary Conditions Essen
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Exercise 0 - Ideal ballistics • M
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Exercise 0 - Ideal ballistics (5)
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Exercise 1 - Suspended mass (3) •
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Exercise 1 - Suspended mass (7) •
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Exercise 2 - Wave propagation (4)
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Exercise 3 - Impact on Cooling Towe
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TITLE: PMAT04: motion of projectile
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sinon; tra2 = tra2 et ele; finsi; f
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Some results: horizontal and vertic
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PMAT01E This test is similar to PMA
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Hence: 11 −8 ES 2× 10 ⋅ 2.5×
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The stress history is: Note that th
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Analytical TEST11 Same as TEST01 bu
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Comparison of natural vs. engineeri
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The total external forces at the tw
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TEST13 Same as TEST01 but uses a 10
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The mass returns at the initial pos
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TEST22 To verify the independence o
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Linear dynamic analysis Consider th
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• The two waves f and g propagate
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Analytical solution For the bar imp
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Note that we have also put the Pois
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BARI08 We study the effect of the t
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ENDPLAY *==========================
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BARI10 Same as BARI09 but compares
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The system is initially at rest, an
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CAST MESH TRID NONL LAGR $ $ Dimens
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Final deformation (with superposed
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Detailed Contents • Modeling the
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Modeling the fluid domain • The f
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Euler equations (3) • For a compr
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Time integration Each time incremen
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Time integration (5) 10. Account fo
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Euler Equations (FV) • They are w
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Mesh rezoning - motivations • Rez
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Giuliani’s automatic rezoning •
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• Analytical solution (self-simil
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Shock tube (6) • Influence of pse
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Exercise 2 - Explosion in air-fille
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Exercise 3 - Bubble expansion in a
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Exercise 4 - External blast on two
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Geometric data: The calculation is
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SHOC01 Eulerian, “average” pseu
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COUR 7 'ro_a' ECRO COMP 2 ELEM LECT
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Analytical Conclusion: the pseudo-v
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SHOC13 Eulerian, very low pseudo-vi
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Analytical General conclusions: •
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The inverse path is not so straight
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The input files (mesh generation by
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Geometric data: The calculation is
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COUR 1 'dx_4' DEPL COMP 1 NOEU LECT
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TANK02 Eulerian solution: the whole
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The final pressure distribution is:
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TUBE06 Lagrangian solution: the who
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And the final velocity distribution
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The computed displacements are: To
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43 30 30 43 44 31 31 44 45 32 32 45
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Geometric data: External blast in a
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abs4 = dall (p4 d 28 p4u) (p4u d 40
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Geometric data: Internal blast in a
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air = air1 ET air2 ET air3 ET air4
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COURBE 8 'P e_p12' ECROU COMP 1 lec
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3D axisymmetric simulation: JWLS3G
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point lect 1 term elem lect 1 term
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Universitat Politècnica de Catalun
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• Motivation Detailed Contents
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FSI Classification FSI for compress
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The 2-D plane case (2) Use geometri
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Classification of FSI algorithms
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The FSA algorithm (4) The case of s
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The FSCR algorithm Combination of F
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Application to Finite Volumes (3) 2
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Exercise 2 - Explosions in simple d
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Exercise/Example 3 - Wave propagati
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Exercise/Example 4 - CONT problem (
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Exercise/Example 5 - Explosion in a
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Exercise/Example 6 : Woodward-Colel
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Geometry: Exercise/Example 8 Steam
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Exercise/Example 9 Explosion in Sec
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Exercise/Example 9 Explosion in Sec
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Boundary Condition Elements: CLxx (
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Exercise/Example 11 - Perforated Pl
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Exercise/Example 12 - Sloshing (3)
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DIME PT3L 23 PT2L 143 FL24 145 ED01
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The final pressure field in the flu
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ALE solution with FSA: it is not po
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120 119 138 139 121 120 139 140 122
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and the final velocity field: The s
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The final velocities: The final liq
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*----------------------------------
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TWIS07 We study the phenomenon by a
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This is a well-known reactor safety
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1.53330E+00 1.32310E+01 1.15000E+00
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200 199 239 240 200 200 200 240 241
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*----------------------------------
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The final fluid pressures: CONT02 T
Page 241 and 242: The final fluid velocities: The fin
Page 243 and 244: This example consists in a long 3D
Page 245 and 246: GEOM FL38 flui Q4GS stru TERM COMP
Page 248 and 249: Detail of first diaphragm: Detail o
Page 250 and 251: BOUNDARY CONDITIONS: The step is en
Page 252 and 253: The EUROPLEXUS input file reads: WO
Page 254 and 255: WOCO3D The mesh generation file (K2
Page 256 and 257: * RESU ALIC GARD PSCR * SORT GRAP *
Page 258 and 259: PT3L 16389 PT6L 504 NBLE 16389 NALE
Page 260 and 261: Final pressure distribution: 4
Page 262 and 263: BOUNDARY CONDITIONS: The vessel is
Page 264 and 265: as01=daller c1 c2 c3 c4 plan; * c1=
Page 266 and 267: *trac oeil cach fluidstr; *opti don
Page 268 and 269: cam3=cam31 et cam32; camb=cam1 et c
Page 270 and 271: log 1 dtml REZO GAM0 0.5 FLMP EPS1
Page 272 and 273: Final structure deformation: Final
Page 274 and 275: LOADING: The event is initiated by
Page 276 and 277: FLUT RO .242777373 EINT 6.865E5 GAM
Page 278 and 279: Final structure velocities: 6
Page 280 and 281: RESULTS: A paper by Bermudez and Ro
Page 282 and 283: The applied displacement and the co
Page 284 and 285: PROBLEM: A rigid tank with a deform
Page 286: The EUROPLEXUS input file reads: GR
Page 289 and 290: PROBLEM: A rigid tank with rigid or
Page 291: COMP EPAI 0.005 LECT 101 102 103 10
Page 295 and 296: ! VARI DEPL VITE ECRO ! fich alic t
Page 297 and 298: The final pressures in the rigid an
Page 299 and 300: LOADING: A constant gravity in the
Page 301 and 302: Some results: intermediate and fina
Page 305 and 306: Universitat Politècnica de Catalun
Page 307 and 308: ALE description of structures (2)
Page 309 and 310: Example 1 - Taylor bar impact (3) B
Page 311 and 312: Example 3 - Coining (3) Influence o
Page 313 and 314: • Tentative classification: Non-c
Page 315 and 316: Example 4 - Explosion in a 2D box (
Page 317 and 318: Example 6 - LOCA in the HDR (2) A -
Page 319 and 320: Examples of “Slow” Transient Co
Page 321 and 322: Examples of Fast Transient Impact
Page 323 and 324: Components of Contact-Impact Method
Page 325 and 326: Shortcomings • Slender or distort
Page 327 and 328: Example - Bar impact • (See Part
Page 329 and 330: Example 7b - Indentation (2) • 2D
Page 331 and 332: Example 7b - Indentation (6) • 3D
Page 333 and 334: Smoothed Particles Hydrodynamics (C
Page 335 and 336: SPH Formulation (2) • Basic idea:
Page 337 and 338: SPH impact [Courtesy of Samtech/Son
Page 339 and 340: PRGL01: Example 8 - SPH impacts (Co
Page 341 and 342: Spectral Elements • Motivation: l
Page 343 and 344:
Spectral Elements (5) Convergence p
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Example 9 - Closed FE/SE interface
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Example 11 - Cylindrical valley 85
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Performance Optimization • All ex
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Time Step Partitioning (4) • Intr
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Time Step Partitioning (8) • Acti
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Treatment of links in partitioning
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Example 12a - Taylor bar impact rev
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Coupling at the Interfaces • Two
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Coupling at the Interfaces (5) MU T
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Coupling at the Interfaces (9) Time
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Multiple scales in time (3) • Exp
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Multiple scales in space • Furthe
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Multiple scales in frequency • So
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Example: power plant 133 Example: p
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Example: aircraft (3) Thanks to CPU
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Example 14 - Domains in 3D • Thic
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Example 15 - Bar Impact Revisited (
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* mesh=stru et symax et viti et lil
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The displacements are: 4
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c2=p1 d 8 p2; c3=p2 d 20 p3; c4=p3
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The resulting final deformed mesh w
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TERM *-----------------------------
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Geometric data and materials: The b
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BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56
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INFS02 We use a twice finer fluid m
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FREQ 1 GOTR LOOP 60 OFFS FICH AVI C
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Problem description: This example i
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*----------------------------------
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The final velocities: The final for
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*----------------------------------
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The final deformed mesh is: The fin
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pc = 4.5 -1 -1.5; pd = 5.5 -1 -1.5;
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The initial configuration (with par
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TITLE: Indentation problem. PROBLEM
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cp = p0 d 10 p13; elim tol (piece e
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The final velocities: The final dis
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The input file is: INDE - 13 ECHO !
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The final displacement norm: The fi
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elim tol (piece et cp); c_p = piece
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The final deformed shape is: 13
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Numerical Solutions PRGL01 Simplifi
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FOV 2.48819E+01 SCEN GEOM NAVI FREE
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ROMA01 Final plastic streen in the
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SONA01 7
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Final density in the projectile: Fi
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opti echo 0; opti donn 'D:\Users\Fo
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* opti dime 2 elem qua4; p0 = 0 0;
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The final X-displacement in the hyb
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* opti dime 2 elem qua4; opti titr
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VALLPS This calculation assumes a p
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The receiver signal in the coupled
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Problem description: This example r
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CALC TINI 0. TFIN 40.E-3 *=========
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REPETER BCL2 (2); REPETER BCL3 (2);
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*----------------------------------
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The tip displacement in the referen
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LOG 1 DPSD *-----------------------
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TRAC CACH OEIL2 ZONE1; TRAC CACH OE
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The tip displacement in the referen
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$ INIT VITE 2 -227. LECT VITI TERM
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* AXTE 1000.0 'Time [ms]' * COUR 1
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sq41=sq41 coul 'TURQ'; sq42=sq42 co
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The displacements in the case with
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European Commission DG Joint Resear
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