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PT3L 16389 PT6L 504 NBLE 16389 NALE 163 MNTI 10 NDVC 72438 NEPE 253328 ECRO 398076 MC34 18796 MC38 3500 FL34 18940 FL38 3400 COQI 840 MTPO 504 MTEL 840 CL3I 840 TERM $----------------------------------------------------------------------$ GEOM FL34 EXFETFL AIFETFL MC34 EXFETMC AIFETMC FL38 EXFEHFL AIFEHFL MC38 EXFEHMC AIFEHMC COQI WALTFL WALTMC WALHFL WALHMC CL3I PIMP TERM $----------------------------------------------------------------------$ GRIL LAGR LECT WALTFL WALTMC WALHFL WALHMC TERM ALE LECT EXFETFL AIFETFL EXFETMC AIFETMC EXFEHFL AIFEHFL EXFEHMC AIFEHMC TERM AUTO AUTR $----------------------------------------------------------------------$ EPAI 2.5e-3 LECT WALTFL WALTMC WALHFL WALHMC TERM $----------------------------------------------------------------------$ MATE $ $....( STRUCTURE ).....................................................$ VM23 RO 5000. YOUN 1.0E09 NU 0.3 ELAS 1.0E09 TRAC 1 1.0E+09 1.0E+00 LECT WALTFL WALTMC WALHFL WALHMC TERM $ $....( FLUID ).........................................................$ $ (Volume of the 4 high-energy zones: Vol=.5448 m^3 $ $ ------ Flut material ------- $ $ High energy zone FLUT RO 2. EINT 5.E5 GAMM 1.5 PB 0 ITER 1 ALF0 1 BET0 1 KINT 0 AHGF 0 CL 0.0 CQ 2.00 PMIN 0 NUM 1 LECT EXFETFL EXFEHFL TERM $ Low energy zone FLUT RO 2. EINT 1.E5 GAMM 1.5 PB 0 ITER 1 ALF0 1 BET0 1 KINT 0 AHGF 0 CL 0.0 CQ 2.00 PMIN 0 NUM 1 LECT AIFETFL AIFEHFL TERM $ $ ------ Mcgp material ------- $ MCGP NCOM 1 R 10000 COMP 'Oxigen1' PM 20. CV1 20000 CV2 0 CV3 0 LECT EXFETMC AIFETMC EXFEHMC AIFEHMC TERM $ $ ------ Imposed Pressure ------- $ IMPE PIMP RO 1.0 PREF 0.0 PRES 1.0E5 TABP 2 0.0 1.0 1.0 1.0 LECT PIMP TERM $ $----------------------------------------------------------------------$ INIT MCOM COMP 'Oxigen1' MFRA 1.0 LECT EXFETMC AIFETMC EXFEHMC AIFEHMC TERM PRES 1.E5 LECT AIFVTMC AIFVHMC TERM PRES 5.E5 LECT EXFVTMC EXFVHMC TERM TEMP 100. LECT AIFVTMC AIFVHMC TERM TEMP 500. LECT EXFVTMC EXFVHMC TERM $----------------------------------------------------------------------$ OPTI FSCR LINK COUP BLOQ 1 LECT bloc1 TERM 2 LECT bloc2 TERM 3 LECT bloc3 TERM 123 LECT blocall TERM 2
CONT SPLA NX 1 NY 0 NZ 0 LECT symx TERM CONT SPLA NX 0 NY 1 NZ 0 LECT symy TERM FSA LECT fsan TERM $----------------------------------------------------------------------$ ECRI fich form spli k200 TFRE 1.e-3 poin tous vari depl vite mcxx ecro ecrc lect 1 2 4 term $TRAC FORM IDEA TFRE 1.e-3 $VARI DEPL MCVA FLVA $POIN LECT LAGR TERM $ELEM LECT WALTFL WALTMC WALHFL WALHMC TERM $ TRAC TPLO TFRE 25.E-6 DESC 'EXFS13' POIN LECT TPLNTFL TPLNTMC TPLNHFL TPLNHMC TERM $----------------------------------------------------------------------$ OPTI NOTE OPTI MC ORDR 2 LOG 1 REZO GAM0 0.5 LIAI MVRE MODU csta 0.5 $----------------------------------------------------------------------$ CALC TINI 0 TEND 20.E-3 $----------------------------------------------------------------------$ FIN $----------------------------------------------------------------------$ Some results: intermediate pressure distribution: 3
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European Laboratory for Structural
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Proceedings of a Course on: Numeric
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Programme of the Course 1. Introduc
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Credits & Acknowledgments • Struc
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Introductory Example (4) 7 Applicat
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x Computational Framework • Gover
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n+ 1 n ∆t n n+ 1 u = u + ( u + u
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Scheme start-up and marching (2)
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Stress Update • To solve the equi
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Geometric non-linearities (3) Set u
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Essential Boundary Conditions Essen
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Exercise 0 - Ideal ballistics • M
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Exercise 0 - Ideal ballistics (5)
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Exercise 1 - Suspended mass (3) •
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Exercise 1 - Suspended mass (7) •
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Exercise 2 - Wave propagation (4)
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Exercise 3 - Impact on Cooling Towe
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TITLE: PMAT04: motion of projectile
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sinon; tra2 = tra2 et ele; finsi; f
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Some results: horizontal and vertic
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PMAT01E This test is similar to PMA
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Hence: 11 −8 ES 2× 10 ⋅ 2.5×
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The stress history is: Note that th
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Analytical TEST11 Same as TEST01 bu
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Comparison of natural vs. engineeri
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The total external forces at the tw
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TEST13 Same as TEST01 but uses a 10
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The mass returns at the initial pos
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TEST22 To verify the independence o
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Linear dynamic analysis Consider th
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• The two waves f and g propagate
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Analytical solution For the bar imp
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Note that we have also put the Pois
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BARI08 We study the effect of the t
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ENDPLAY *==========================
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BARI10 Same as BARI09 but compares
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The system is initially at rest, an
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CAST MESH TRID NONL LAGR $ $ Dimens
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Final deformation (with superposed
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Detailed Contents • Modeling the
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Modeling the fluid domain • The f
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Euler equations (3) • For a compr
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Time integration Each time incremen
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Time integration (5) 10. Account fo
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Euler Equations (FV) • They are w
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Mesh rezoning - motivations • Rez
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Giuliani’s automatic rezoning •
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• Analytical solution (self-simil
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Shock tube (6) • Influence of pse
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Exercise 2 - Explosion in air-fille
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Exercise 3 - Bubble expansion in a
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Exercise 4 - External blast on two
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Geometric data: The calculation is
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SHOC01 Eulerian, “average” pseu
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COUR 7 'ro_a' ECRO COMP 2 ELEM LECT
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Analytical Conclusion: the pseudo-v
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SHOC13 Eulerian, very low pseudo-vi
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Analytical General conclusions: •
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The inverse path is not so straight
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The input files (mesh generation by
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Geometric data: The calculation is
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COUR 1 'dx_4' DEPL COMP 1 NOEU LECT
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TANK02 Eulerian solution: the whole
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The final pressure distribution is:
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TUBE06 Lagrangian solution: the who
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And the final velocity distribution
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The computed displacements are: To
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43 30 30 43 44 31 31 44 45 32 32 45
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Geometric data: External blast in a
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abs4 = dall (p4 d 28 p4u) (p4u d 40
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Geometric data: Internal blast in a
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air = air1 ET air2 ET air3 ET air4
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COURBE 8 'P e_p12' ECROU COMP 1 lec
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3D axisymmetric simulation: JWLS3G
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point lect 1 term elem lect 1 term
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Universitat Politècnica de Catalun
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• Motivation Detailed Contents
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FSI Classification FSI for compress
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The 2-D plane case (2) Use geometri
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Classification of FSI algorithms
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The FSA algorithm (4) The case of s
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The FSCR algorithm Combination of F
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Application to Finite Volumes (3) 2
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Exercise 2 - Explosions in simple d
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Exercise/Example 3 - Wave propagati
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Exercise/Example 4 - CONT problem (
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Exercise/Example 5 - Explosion in a
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Exercise/Example 6 : Woodward-Colel
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Geometry: Exercise/Example 8 Steam
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Exercise/Example 9 Explosion in Sec
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Exercise/Example 9 Explosion in Sec
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Boundary Condition Elements: CLxx (
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Exercise/Example 11 - Perforated Pl
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Exercise/Example 12 - Sloshing (3)
Page 207 and 208: Exercise/Example 12 - Sloshing (7)
Page 209: Exercise/Example 12 - Sloshing (11)
Page 214 and 215: DIME PT3L 23 PT2L 143 FL24 145 ED01
Page 216 and 217: The final pressure field in the flu
Page 218 and 219: ALE solution with FSA: it is not po
Page 220 and 221: 120 119 138 139 121 120 139 140 122
Page 222 and 223: and the final velocity field: The s
Page 224 and 225: The final velocities: The final liq
Page 226 and 227: *----------------------------------
Page 228 and 229: TWIS07 We study the phenomenon by a
Page 231 and 232: This is a well-known reactor safety
Page 233 and 234: 1.53330E+00 1.32310E+01 1.15000E+00
Page 235 and 236: 200 199 239 240 200 200 200 240 241
Page 237 and 238: *----------------------------------
Page 239 and 240: The final fluid pressures: CONT02 T
Page 241 and 242: The final fluid velocities: The fin
Page 243 and 244: This example consists in a long 3D
Page 245 and 246: GEOM FL38 flui Q4GS stru TERM COMP
Page 248 and 249: Detail of first diaphragm: Detail o
Page 250 and 251: BOUNDARY CONDITIONS: The step is en
Page 252 and 253: The EUROPLEXUS input file reads: WO
Page 254 and 255: WOCO3D The mesh generation file (K2
Page 256 and 257: * RESU ALIC GARD PSCR * SORT GRAP *
Page 260 and 261: Final pressure distribution: 4
Page 262 and 263: BOUNDARY CONDITIONS: The vessel is
Page 264 and 265: as01=daller c1 c2 c3 c4 plan; * c1=
Page 266 and 267: *trac oeil cach fluidstr; *opti don
Page 268 and 269: cam3=cam31 et cam32; camb=cam1 et c
Page 270 and 271: log 1 dtml REZO GAM0 0.5 FLMP EPS1
Page 272 and 273: Final structure deformation: Final
Page 274 and 275: LOADING: The event is initiated by
Page 276 and 277: FLUT RO .242777373 EINT 6.865E5 GAM
Page 278 and 279: Final structure velocities: 6
Page 280 and 281: RESULTS: A paper by Bermudez and Ro
Page 282 and 283: The applied displacement and the co
Page 284 and 285: PROBLEM: A rigid tank with a deform
Page 286: The EUROPLEXUS input file reads: GR
Page 289 and 290: PROBLEM: A rigid tank with rigid or
Page 291 and 292: COMP EPAI 0.005 LECT 101 102 103 10
Page 293 and 294: Numerical Solution (flexible bottom
Page 295 and 296: ! VARI DEPL VITE ECRO ! fich alic t
Page 297 and 298: The final pressures in the rigid an
Page 299 and 300: LOADING: A constant gravity in the
Page 301 and 302: Some results: intermediate and fina
Page 305 and 306: Universitat Politècnica de Catalun
Page 307 and 308: ALE description of structures (2)
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Example 1 - Taylor bar impact (3) B
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Example 3 - Coining (3) Influence o
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• Tentative classification: Non-c
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Example 4 - Explosion in a 2D box (
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Example 6 - LOCA in the HDR (2) A -
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Examples of “Slow” Transient Co
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Examples of Fast Transient Impact
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Components of Contact-Impact Method
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Shortcomings • Slender or distort
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Example - Bar impact • (See Part
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Example 7b - Indentation (2) • 2D
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Example 7b - Indentation (6) • 3D
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Smoothed Particles Hydrodynamics (C
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SPH Formulation (2) • Basic idea:
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SPH impact [Courtesy of Samtech/Son
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PRGL01: Example 8 - SPH impacts (Co
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Spectral Elements • Motivation: l
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Spectral Elements (5) Convergence p
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Example 9 - Closed FE/SE interface
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Example 11 - Cylindrical valley 85
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Performance Optimization • All ex
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Time Step Partitioning (4) • Intr
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Time Step Partitioning (8) • Acti
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Treatment of links in partitioning
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Example 12a - Taylor bar impact rev
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Coupling at the Interfaces • Two
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Coupling at the Interfaces (5) MU T
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Coupling at the Interfaces (9) Time
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Multiple scales in time (3) • Exp
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Multiple scales in space • Furthe
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Multiple scales in frequency • So
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Example: power plant 133 Example: p
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Example: aircraft (3) Thanks to CPU
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Example 14 - Domains in 3D • Thic
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Example 15 - Bar Impact Revisited (
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* mesh=stru et symax et viti et lil
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The displacements are: 4
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c2=p1 d 8 p2; c3=p2 d 20 p3; c4=p3
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The resulting final deformed mesh w
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TERM *-----------------------------
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Geometric data and materials: The b
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BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56
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INFS02 We use a twice finer fluid m
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FREQ 1 GOTR LOOP 60 OFFS FICH AVI C
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Problem description: This example i
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*----------------------------------
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The final velocities: The final for
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*----------------------------------
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The final deformed mesh is: The fin
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pc = 4.5 -1 -1.5; pd = 5.5 -1 -1.5;
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The initial configuration (with par
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TITLE: Indentation problem. PROBLEM
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cp = p0 d 10 p13; elim tol (piece e
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The final velocities: The final dis
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The input file is: INDE - 13 ECHO !
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The final displacement norm: The fi
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elim tol (piece et cp); c_p = piece
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The final deformed shape is: 13
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Numerical Solutions PRGL01 Simplifi
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FOV 2.48819E+01 SCEN GEOM NAVI FREE
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ROMA01 Final plastic streen in the
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SONA01 7
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Final density in the projectile: Fi
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opti echo 0; opti donn 'D:\Users\Fo
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* opti dime 2 elem qua4; p0 = 0 0;
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The final X-displacement in the hyb
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* opti dime 2 elem qua4; opti titr
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VALLPS This calculation assumes a p
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The receiver signal in the coupled
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Problem description: This example r
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CALC TINI 0. TFIN 40.E-3 *=========
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REPETER BCL2 (2); REPETER BCL3 (2);
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*----------------------------------
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The tip displacement in the referen
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LOG 1 DPSD *-----------------------
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TRAC CACH OEIL2 ZONE1; TRAC CACH OE
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The tip displacement in the referen
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$ INIT VITE 2 -227. LECT VITI TERM
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* AXTE 1000.0 'Time [ms]' * COUR 1
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sq41=sq41 coul 'TURQ'; sq42=sq42 co
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The displacements in the case with
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European Commission DG Joint Resear
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