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The input file: INFS - 02 *----------------------------------------------------------------------- ECHO CONV win CAST MESH *-----------------------------------------------------------Problem type DPLA NONL ALE *-----------------------------------------------------------Dimensioning DIME PT3L 5 PT2L 63 FL24 48 ED01 4 ZONE 2 NALE 9 NBLE 63 MTPO 6 MTEL 1 TERM *---------------------------------------------------------------Geometry GEOM FL24 FLUI ED01 STRU TERM *--------------------------------------------------Geometric Complements EPAI 0.0001 LECT STRU TERM coul blan lect flui term *------------------------------------------------------------Grid motion GRIL LAGR LECT stru TERM EULE LECT fsan TERM ALE LECT FLUI TERM AUTO AUTR *----------------------------------------------------------Material data MATE VM23 RO 7800. YOUNG 1.6E11 NU 0.333 ELAS 1.05E8 TRAC 2 1.05E8 .656256E-3 1.6105E10 1.00066 LECT STRU TERM FLUT RO 1.22 EINT 3.046E6 GAMM 1.269 PB 0 ITER 1 ALF0 1 BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56 PMIN 0 NUM 1 LECT BULL TERM FLUT RO 0.1237 EINT 3.046E6 GAMM 1.269 PB 0 ITER 1 ALF0 1 BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56 PMIN 0 NUM 1 LECT GAS TERM *----------------------------------------------------Boundary conditions LINK COUP BLOQ 1 LECT BLOQX TERM 2 LECT BLOQY TERM FSA NCFS LECT fsan TERM *----------------------------------------------------------------Outputs ECRI COOR DEPL VITE CONT ECRO FINT FEXT TFRE 1.0E-3 FICH K200 TFRE 1.E-3 POIN TOUS VARI DEPL VITE FEXT ECRO ECRC LECT 1 TERM FICH TPLO FREQ 1 DESC 'INFS02' POIN LECT 57 59 61 65 66 67 TERM ELEM LECT 1 TERM FICH ALIC TEMP FREQ 1 POIN LECT 57 59 61 65 66 67 TERM ELEM LECT 1 TERM *----------------------------------------------------------------Options OPTI NOTE csta 0.5 liaj log 1 REZO GAM0 0.5 *--------------------------------------------------Transient calculation CALCUL TINI 0 TEND 4.E-3 *==============================================================ANIMATION PLAY CAME 1 EYE 2.00000E+00 2.14602E+00 1.46675E+01 ! Q 1.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 VIEW 0.00000E+00 0.00000E+00 -1.00000E+00 RIGH 1.00000E+00 0.00000E+00 0.00000E+00 UP 0.00000E+00 1.00000E+00 0.00000E+00 FOV 2.48819E+01 SCEN GEOM NAVI FREE !ISO FILI FIEL ECRO 1 SCAL USER PROG 1.0D5 PAS 1.0D4 2.3D5 TERM !TEXT ISCA VECT SCCO SCAL USER PROG 0 PAS 50 650 TERM TEXT VSCA colo pape sler cam1 1 nfra 1 trac offs fich avi nocl nfto 62 fps 5 kfre 10 comp -1 6
FREQ 1 GOTR LOOP 60 OFFS FICH AVI CONT NOCL GOTR OFFS FICH AVI CONT !obje lect flui term REND !obje lect flui term REND !obje lect flui term REND ENDPLAY *=========================================================POST-TREATMENT SUIT Post-treatment ECHO RESU ALIC TEMP GARD PSCR SORT GRAP AXTE 1000.0 'Time [ms]' *------------------------------------------------------Curve definitions COUR 1 'dy_65' DEPL COMP 2 NOEU LECT 65 TERM COUR 2 'dy_66' DEPL COMP 2 NOEU LECT 66 TERM COUR 3 'dy_67' DEPL COMP 2 NOEU LECT 67 TERM COUR 4 'vx_59' VITE COMP 1 NOEU LECT 59 TERM COUR 5 'vy_59' VITE COMP 2 NOEU LECT 59 TERM *------------------------------------------------------------------Plots trac 1 2 3 axes 1.0 'DISPL. [M]' trac 4 5 axes 1.0 'V [M/S]' *--------------------------------------------------Results qualification QUAL DEPL COMP 2 LECT 65 TERM REFE 1.05700E+0 TOLE 5.E-3 DEPL COMP 2 LECT 66 TERM REFE 1.33322E+0 TOLE 5.E-3 DEPL COMP 2 LECT 67 TERM REFE 1.03977E+0 TOLE 5.E-3 *======================================================================= FIN 7
Page 1 and 2:
European Laboratory for Structural
Page 3 and 4:
Proceedings of a Course on: Numeric
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Programme of the Course 1. Introduc
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Credits & Acknowledgments • Struc
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Introductory Example (4) 7 Applicat
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x Computational Framework • Gover
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n+ 1 n ∆t n n+ 1 u = u + ( u + u
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Scheme start-up and marching (2)
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Stress Update • To solve the equi
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Geometric non-linearities (3) Set u
Page 24 and 25:
Essential Boundary Conditions Essen
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Exercise 0 - Ideal ballistics • M
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Exercise 0 - Ideal ballistics (5)
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Exercise 1 - Suspended mass (3) •
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Exercise 1 - Suspended mass (7) •
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Exercise 2 - Wave propagation (4)
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Exercise 3 - Impact on Cooling Towe
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TITLE: PMAT04: motion of projectile
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sinon; tra2 = tra2 et ele; finsi; f
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Some results: horizontal and vertic
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PMAT01E This test is similar to PMA
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Hence: 11 −8 ES 2× 10 ⋅ 2.5×
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The stress history is: Note that th
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Analytical TEST11 Same as TEST01 bu
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Comparison of natural vs. engineeri
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The total external forces at the tw
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TEST13 Same as TEST01 but uses a 10
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The mass returns at the initial pos
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TEST22 To verify the independence o
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Linear dynamic analysis Consider th
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• The two waves f and g propagate
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Analytical solution For the bar imp
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Note that we have also put the Pois
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BARI08 We study the effect of the t
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ENDPLAY *==========================
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BARI10 Same as BARI09 but compares
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The system is initially at rest, an
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CAST MESH TRID NONL LAGR $ $ Dimens
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Final deformation (with superposed
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Detailed Contents • Modeling the
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Modeling the fluid domain • The f
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Euler equations (3) • For a compr
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Time integration Each time incremen
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Time integration (5) 10. Account fo
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Euler Equations (FV) • They are w
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Mesh rezoning - motivations • Rez
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Giuliani’s automatic rezoning •
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• Analytical solution (self-simil
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Shock tube (6) • Influence of pse
Page 110 and 111:
Exercise 2 - Explosion in air-fille
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Exercise 3 - Bubble expansion in a
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Exercise 4 - External blast on two
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Geometric data: The calculation is
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SHOC01 Eulerian, “average” pseu
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COUR 7 'ro_a' ECRO COMP 2 ELEM LECT
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Analytical Conclusion: the pseudo-v
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SHOC13 Eulerian, very low pseudo-vi
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Analytical General conclusions: •
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The inverse path is not so straight
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The input files (mesh generation by
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Geometric data: The calculation is
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COUR 1 'dx_4' DEPL COMP 1 NOEU LECT
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TANK02 Eulerian solution: the whole
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The final pressure distribution is:
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TUBE06 Lagrangian solution: the who
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And the final velocity distribution
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The computed displacements are: To
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43 30 30 43 44 31 31 44 45 32 32 45
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Geometric data: External blast in a
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abs4 = dall (p4 d 28 p4u) (p4u d 40
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Geometric data: Internal blast in a
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air = air1 ET air2 ET air3 ET air4
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COURBE 8 'P e_p12' ECROU COMP 1 lec
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3D axisymmetric simulation: JWLS3G
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point lect 1 term elem lect 1 term
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Universitat Politècnica de Catalun
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• Motivation Detailed Contents
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FSI Classification FSI for compress
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The 2-D plane case (2) Use geometri
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Classification of FSI algorithms
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The FSA algorithm (4) The case of s
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The FSCR algorithm Combination of F
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Application to Finite Volumes (3) 2
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Exercise 2 - Explosions in simple d
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Exercise/Example 3 - Wave propagati
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Exercise/Example 4 - CONT problem (
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Exercise/Example 5 - Explosion in a
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Exercise/Example 6 : Woodward-Colel
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Geometry: Exercise/Example 8 Steam
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Exercise/Example 9 Explosion in Sec
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Exercise/Example 9 Explosion in Sec
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Boundary Condition Elements: CLxx (
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Exercise/Example 11 - Perforated Pl
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Exercise/Example 12 - Sloshing (3)
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DIME PT3L 23 PT2L 143 FL24 145 ED01
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The final pressure field in the flu
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ALE solution with FSA: it is not po
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120 119 138 139 121 120 139 140 122
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and the final velocity field: The s
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The final velocities: The final liq
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*----------------------------------
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TWIS07 We study the phenomenon by a
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This is a well-known reactor safety
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1.53330E+00 1.32310E+01 1.15000E+00
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200 199 239 240 200 200 200 240 241
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*----------------------------------
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The final fluid pressures: CONT02 T
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The final fluid velocities: The fin
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This example consists in a long 3D
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GEOM FL38 flui Q4GS stru TERM COMP
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Detail of first diaphragm: Detail o
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BOUNDARY CONDITIONS: The step is en
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The EUROPLEXUS input file reads: WO
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WOCO3D The mesh generation file (K2
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* RESU ALIC GARD PSCR * SORT GRAP *
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PT3L 16389 PT6L 504 NBLE 16389 NALE
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Final pressure distribution: 4
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BOUNDARY CONDITIONS: The vessel is
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as01=daller c1 c2 c3 c4 plan; * c1=
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*trac oeil cach fluidstr; *opti don
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cam3=cam31 et cam32; camb=cam1 et c
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log 1 dtml REZO GAM0 0.5 FLMP EPS1
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Final structure deformation: Final
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LOADING: The event is initiated by
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FLUT RO .242777373 EINT 6.865E5 GAM
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Final structure velocities: 6
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RESULTS: A paper by Bermudez and Ro
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The applied displacement and the co
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PROBLEM: A rigid tank with a deform
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The EUROPLEXUS input file reads: GR
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PROBLEM: A rigid tank with rigid or
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COMP EPAI 0.005 LECT 101 102 103 10
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Numerical Solution (flexible bottom
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! VARI DEPL VITE ECRO ! fich alic t
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The final pressures in the rigid an
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LOADING: A constant gravity in the
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Some results: intermediate and fina
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Universitat Politècnica de Catalun
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ALE description of structures (2)
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Example 1 - Taylor bar impact (3) B
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Example 3 - Coining (3) Influence o
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• Tentative classification: Non-c
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Example 4 - Explosion in a 2D box (
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Example 6 - LOCA in the HDR (2) A -
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Examples of “Slow” Transient Co
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Examples of Fast Transient Impact
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Components of Contact-Impact Method
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Shortcomings • Slender or distort
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Example - Bar impact • (See Part
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Example 7b - Indentation (2) • 2D
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Example 7b - Indentation (6) • 3D
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Smoothed Particles Hydrodynamics (C
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SPH Formulation (2) • Basic idea:
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SPH impact [Courtesy of Samtech/Son
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PRGL01: Example 8 - SPH impacts (Co
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Spectral Elements • Motivation: l
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Spectral Elements (5) Convergence p
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Example 9 - Closed FE/SE interface
Page 347 and 348: Example 11 - Cylindrical valley 85
Page 349 and 350: Performance Optimization • All ex
Page 351 and 352: Time Step Partitioning (4) • Intr
Page 353 and 354: Time Step Partitioning (8) • Acti
Page 355 and 356: Treatment of links in partitioning
Page 357 and 358: Example 12a - Taylor bar impact rev
Page 359 and 360: Coupling at the Interfaces • Two
Page 361 and 362: Coupling at the Interfaces (5) MU T
Page 363 and 364: Coupling at the Interfaces (9) Time
Page 365 and 366: Multiple scales in time (3) • Exp
Page 367 and 368: Multiple scales in space • Furthe
Page 369 and 370: Multiple scales in frequency • So
Page 371 and 372: Example: power plant 133 Example: p
Page 373 and 374: Example: aircraft (3) Thanks to CPU
Page 375 and 376: Example 14 - Domains in 3D • Thic
Page 377: Example 15 - Bar Impact Revisited (
Page 382 and 383: * mesh=stru et symax et viti et lil
Page 384 and 385: The displacements are: 4
Page 386 and 387: c2=p1 d 8 p2; c3=p2 d 20 p3; c4=p3
Page 388 and 389: The resulting final deformed mesh w
Page 390 and 391: TERM *-----------------------------
Page 393 and 394: Geometric data and materials: The b
Page 395 and 396: BET0 1 KINT 0 AHGF 0 CL 0.5 CQ 2.56
Page 397: INFS02 We use a twice finer fluid m
Page 401 and 402: Problem description: This example i
Page 403 and 404: *----------------------------------
Page 405: The final velocities: The final for
Page 408 and 409: *----------------------------------
Page 410 and 411: The final deformed mesh is: The fin
Page 412 and 413: pc = 4.5 -1 -1.5; pd = 5.5 -1 -1.5;
Page 414 and 415: The initial configuration (with par
Page 417 and 418: TITLE: Indentation problem. PROBLEM
Page 419 and 420: cp = p0 d 10 p13; elim tol (piece e
Page 421 and 422: The final velocities: The final dis
Page 423 and 424: The input file is: INDE - 13 ECHO !
Page 425 and 426: The final displacement norm: The fi
Page 427 and 428: elim tol (piece et cp); c_p = piece
Page 429 and 430: The final deformed shape is: 13
Page 431 and 432: Numerical Solutions PRGL01 Simplifi
Page 433 and 434: FOV 2.48819E+01 SCEN GEOM NAVI FREE
Page 435 and 436: ROMA01 Final plastic streen in the
Page 437 and 438: SONA01 7
Page 439: Final density in the projectile: Fi
Page 442 and 443: opti echo 0; opti donn 'D:\Users\Fo
Page 444 and 445: * opti dime 2 elem qua4; p0 = 0 0;
Page 446 and 447: The final X-displacement in the hyb
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* opti dime 2 elem qua4; opti titr
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VALLPS This calculation assumes a p
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The receiver signal in the coupled
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Problem description: This example r
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CALC TINI 0. TFIN 40.E-3 *=========
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REPETER BCL2 (2); REPETER BCL3 (2);
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*----------------------------------
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The tip displacement in the referen
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LOG 1 DPSD *-----------------------
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TRAC CACH OEIL2 ZONE1; TRAC CACH OE
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The tip displacement in the referen
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$ INIT VITE 2 -227. LECT VITI TERM
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* AXTE 1000.0 'Time [ms]' * COUR 1
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sq41=sq41 coul 'TURQ'; sq42=sq42 co
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The displacements in the case with
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European Commission DG Joint Resear
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