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1.1 The Radiation Laws and the Birth of Quantum Mechanics

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QUANTUM MECHANICS I (Dr. T. Br<strong>and</strong>es): Example/Solution Sheets 16<br />

2.10.5 ** A more general definition <strong>of</strong> <strong>the</strong> transfer matrix M (> 30 min)<br />

We consider a one–dimensional potential <strong>of</strong> <strong>the</strong> form<br />

⎧<br />

⎧<br />

⎨ 0,<br />

⎨ ae ikx + be −ikx , −∞ < x ≤ x 1<br />

V (x) = v(x), ψ(x) = φ(x), x 1 < x ≤ x 2<br />

⎩<br />

⎩<br />

0<br />

ce ikx + de −ikx , x 2 < x < ∞<br />

(2.84)<br />

Here, v(x) is an arbitrary real potential. <strong>The</strong> central part φ(x) <strong>of</strong> <strong>the</strong> wave function ψ(x)<br />

<strong>the</strong>refore in general is very difficult to calculate. We can, however, relate <strong>the</strong> coefficients a, b<br />

(left side) with <strong>the</strong> coefficients c, d (right side): if some fixed values for c <strong>and</strong> d are chosen,<br />

this determines <strong>the</strong> solution ψ(x) everywhere on <strong>the</strong> x–axis <strong>and</strong> <strong>the</strong>refore in particular a <strong>and</strong><br />

b. We write this relation as<br />

(<br />

a<br />

b<br />

) ( ) (<br />

M11 M<br />

=<br />

12 c<br />

M 22 d<br />

M 21<br />

)<br />

. (2.85)<br />

a) With ψ(x) also <strong>the</strong> conjugate complex ψ ∗ (x) must be a solution <strong>of</strong> <strong>the</strong> stationary Schrödinger<br />

equation Ĥψ(x) = Eψ(x). Why <br />

b) Take <strong>the</strong> conjugate complex ψ ∗ (x) in (2.84) <strong>and</strong> show that this leads to <strong>the</strong> exchange a ↔ b ∗<br />

<strong>and</strong> c ↔ d ∗ in (2.85).<br />

c) Take <strong>the</strong> conjugate complex <strong>of</strong> <strong>the</strong> whole equation (2.85) <strong>and</strong> compare with <strong>the</strong> equation<br />

you obtain from part b). Show that<br />

d) Consider <strong>the</strong> current density <strong>and</strong> show that<br />

M ∗ 11 = M 22 , M ∗ 12 = M 21 . (2.86)<br />

|a| 2 − |b| 2 = |c| 2 − |d| 2 . (2.87)<br />

Write this equation as a scalar product <strong>of</strong> vectors in <strong>the</strong> form<br />

( ) ( ) ( ) (<br />

1 0 a 1 0 c<br />

(a ∗ b ∗ )<br />

= (c ∗ d ∗ )<br />

0 −1 b<br />

0 −1 d<br />

Use <strong>the</strong> matrix M to derive from this<br />

)<br />

. (2.88)<br />

det(M) = 1. (2.89)<br />

3.11 Axioms <strong>of</strong> <strong>Quantum</strong> <strong>Mechanics</strong> <strong>and</strong> <strong>the</strong> Hilbert Space<br />

3.1<strong>1.1</strong> Definition (2min)<br />

What is a Hilbert space<br />

Def.: A Hilbert space is a complete unitary space.<br />

3.11.2 Orthonormality (5 min)<br />

Consider <strong>the</strong> Hilbert space H <strong>of</strong> wave functions ψ(x) <strong>of</strong> <strong>the</strong> infinite potential well on <strong>the</strong><br />

interval [0, L] with ψ(0) = ψ(L) = 0. Show that <strong>the</strong> basis vectors<br />

√<br />

2<br />

( nπx<br />

)<br />

ψ n (x) =<br />

L sin L<br />

form an orthonormal system.

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