Chapter 11 Chemical Bonds: The Formation of Compounds from ...
Chapter 11 Chemical Bonds: The Formation of Compounds from ...
Chapter 11 Chemical Bonds: The Formation of Compounds from ...
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
ex. <strong>11</strong>.10 write the Lewis structure for H 2 O<br />
step 1 total valence electrons = 2 × 1 + 6 = 8<br />
step 2 the skeleton structure<br />
H O H : O· ·<br />
H<br />
H<br />
step 3 subtract 4 electrons <strong>from</strong> 8<br />
8 – 4 = 4<br />
step 4 distribute 4 electrons around O atom<br />
·· ··<br />
H : O : H—O :<br />
·· |<br />
H<br />
H<br />
ex.<strong>11</strong>.<strong>11</strong> write the Lewis structure for CH 4<br />
step 1 total valence electrons = 4 × 1 + 4 = 8<br />
step 2 H H· ·<br />
H C H H : C : H<br />
··<br />
H<br />
H<br />
step 3 8 – 8 = 0<br />
H<br />
|<br />
H—C—H<br />
|<br />
H<br />
17