Chapter 11 Chemical Bonds: The Formation of Compounds from ...

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ex. 11.14 write the Lewis structure for CO 3 2- step 1 total valence electrons = 4 + 3 × 6 + 2 = 24 step 2 O O· · O C O O : C : O step 3 24 - 6 = 18 step 4 · · : O : ·· ·· ·· : O : C : O : ·· ·· C atom is electron deficient step 5 ·· 2- ·· 2- ·· 2- : O : O : : O : ·· || ·· ·· ·· ·· ·· ·· ·· : O : C : O : : O =C : O : : O : C= O : ·· ·· ·· ·· 20
11.9 Compounds containing polyatomic ions sodium carbonate Na 2 CO 3 has both ionic and covalent bonds ionic bonds exist between Na + and CO 3 2- covalent bonds present between C and O atoms an important difference between ionic and covalent bonds can be demonstrated by dissolving Na 2 CO 3 in water: Na 2 CO 3 (s) water 2 Na + (aq) + CO 3 2- (aq) 21
Page 1 and 2: Chapter 11 Chemical Bonds: The Form
Page 3 and 4: 2. atomic radius • the increase i
Page 5 and 6: 11.2 Lewis structures of atoms meta
Page 7 and 8: consider Na and Cl atoms react with
Page 9 and 10: ex. 11.2 how Mg and Cl combine to f
Page 11 and 12: 11.5 The covalent bond: sharing ele
Page 13 and 14: 11.6 Electronegativity the bond for
Page 15 and 16: carbon dioxide CO 2 is nonpolar O =
Page 17 and 18: ex. 11.10 write the Lewis structure
Page 19: 11.8 Complex Lewis structures for s
Page 23 and 24: 11.11 The valence shell electron pa
Page 25: ex. 11.15 predict the molecular sha

Chapter 11 Chemical Bonds: The Formation of Compounds from ...

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